SQLSat153 Recap
You may not know that this past Saturday ( October 20, 2012) was SQLSaturday 153 in Salt Lake City. If you...
2012-10-24
748 reads
You may not know that this past Saturday ( October 20, 2012) was SQLSaturday 153 in Salt Lake City. If you...
2012-10-24
748 reads
You may not know that this past Saturday ( October 20, 2012) was SQLSaturday 153 in Salt Lake City. If you knew about it, awesome. If you attended –...
2012-10-24
1 reads
Last Thursday I found myself on a journey of sorts. There weren’t any lions or tigers or bears, but there...
2012-10-15
966 reads
Last Thursday I found myself on a journey of sorts. There weren’t any lions or tigers or bears, but there were plenty of “Oh My”‘s. It all began on...
2012-10-15
You ever have those nights consumed by all things SQL?
I do. It happens more than I might like sometimes. Usually...
2012-10-11
922 reads
You ever have those nights consumed by all things SQL? I do. It happens more than I might like sometimes. Usually it happens when there is a work problem...
2012-10-11
High Energy Plankton
In 2022 humans will finally have become their own worst enemies/frenemies. No matter how hard Gore works to...
2012-10-09
1,084 reads
So, what I’d like to know is, what is your most horrifying discovery from your work with SQL Server?
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2012-10-09
Last month I blogged about my absence from the blogosphere. If you want, you can read about it again – here....
2012-10-04
933 reads
Last month I blogged about my absence from the blogosphere. If you want, you can read about it again – here. Granted, it has been a month and I...
2012-10-04
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
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The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
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I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers