SQL Server Quickie #11 – Non Clustered Indexes
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2014-03-03
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(Be sure to checkout the FREE SQLpassion Performance Tuning Training Plan – you get a weekly email packed with all the...
2014-03-03
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(Be sure to checkout the FREE SQLpassion Performance Tuning Training Plan, where you are getting week by week via email...
2014-03-03 (first published: 2014-02-25)
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2014-02-21 (first published: 2014-02-18)
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2014-02-11
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You are a developer and/or DBA and want to learn in a very compact way the essential things about performance...
2014-02-03
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2014-01-29
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(Be sure to checkout the FREE SQLpassion Performance Tuning Training Plan, where you are getting week by week via email...
2014-02-04 (first published: 2014-01-28)
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2014-01-27 (first published: 2014-01-21)
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2014-01-14
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2014-01-07
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One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
By DesertDBA
I haven’t posted in a while (well, not here at least since I’ve been...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
Comments posted to this topic are about the item The Read Committed Snapshot Isolation...
Comments posted to this topic are about the item Working with JSON/JSONB Data in...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers