Countdown to PASS Summit 2012 – 9 to Go – My First Summit
We are less than ten days to the start of PASS Summit 2012. I thought it would be fun to...
2012-10-28
589 reads
We are less than ten days to the start of PASS Summit 2012. I thought it would be fun to...
2012-10-28
589 reads
Over the past few years, I have used Windows Live Writer to create my blog entries on WordPress. Given the...
2012-10-26
2,788 reads
In the 7th article of this series, I will discuss how to manage your partitions with XMLA. We will be...
2012-10-10
641 reads
I recently completed a series of blog posts on www.lessthandot.com on T-SQL Window functions. The enhancements to SQL Server 2012...
2012-09-26
900 reads
In this post, I will progressively go through processing a partition from full process, to incremental process, and finally to...
2012-09-19
801 reads
We are less than two weeks away from SQL Saturday #149 in Minneapolis on September 29, 2012 with two preconference...
2012-09-18
525 reads
First, I need to set the record straight – I am not a systems guy. When I need work done to...
2012-08-30
1,363 reads
When Jason ( B | T ) posted this assignment, I thought it would be a fun topic to write on. Before I...
2012-08-15
508 reads
As I started looking over my event calendar, I was amazed at how many events Magenic is sponsoring, hosting or...
2012-08-14
561 reads
The Open Data Protocol (OData) is an open specification created Microsoft to enable exposing data in a standard way from...
2012-07-23
1,283 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
hi , a new user wants to be able to add sql agent jobs...
Comments posted to this topic are about the item SQL Server Enum Implementation: A...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers