New version of ADO.NET provider for MySQL is available
The following announcement came out this morning on the Annouce mailing list for MySQL:
"MySQL Connector/Net 1.0.7, a new version of...
2005-11-21
1,641 reads
The following announcement came out this morning on the Annouce mailing list for MySQL:
"MySQL Connector/Net 1.0.7, a new version of...
2005-11-21
1,641 reads
David Litchfield has put out a brief (as
he says it, "It's called a brief because there's enough meat to make...
2005-11-19
1,403 reads
There has been some talk on Google Base on the Full Disclosure security
list. I've also seen on another blog about...
2005-11-19
1,394 reads
Catching back up on things. MySQL 5.0 went "RTM" at the end of October.
Haven't had a lot of chances to...
2005-11-19
1,376 reads
For those who use Perl and access SQL Server, MVP Erland Sommarskog has
announced a new module which uses OLE DB...
2005-11-19
1,533 reads
I took part of today off to attend the Denver Woodworking show north of
Denver. I left early because, well, I...
2005-11-18
1,339 reads
I saw Alex's post on installing a named instance of SS2K5 and having
issues with SS2K. I wanted to note that...
2005-11-18
1,383 reads
First, apologies to the Database Daily readers. I'll include one in
next week's issue as well, but the links didn't work...
2005-11-15
1,855 reads
SQL 2005 provides a the new max specifier to be used with varbinary, varchar and nvarchar data types. You can...
2005-11-12
1,288 reads
If you haven't seen it, I started a poll in the editorial today. Check it out and give you answer:...
2005-11-11
1,541 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
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WA:08218154393 Jl. Raya Ciawi No.151, Pakemitan, Kec. Ciawi, Kabupaten Tasikmalaya, Jawa Barat 46156
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers