Trying to Learn SQL Server – Get the Developer Edition
I had a question from a member of our local user group about options to get a legal copy of...
2009-12-15
743 reads
I had a question from a member of our local user group about options to get a legal copy of...
2009-12-15
743 reads
I was tagged earlier this week by Tim Ford to comment on my biggest weakness. I wish I could say...
2009-12-15
785 reads
The short answer is that's where my heart has been. I write because I feel compelled to write. I don't...
2009-12-15
1,022 reads
My friend Ryan Duclos just sent me a reminder about the upcoming Alabama Code Camp on January 23, 2010, in...
2009-12-14
685 reads
I'm reading As Iron Sharpens Iron, which is a classic book on Christian mentoring. Written by Dr. Howard Hendricks and...
2009-12-14
792 reads
In Update #20 I mentioned that I was hoping to get the chapters portfolio for 2010. A few weeks have...
2009-12-14
724 reads
The CIO’s Voice, a blog written by Arun Manansingh, has been mentioned in a number of articles I’ve seen as...
2009-12-14
353 reads
It’s done, though I’m nervous about my laptop repair. The last entry on the machine prior to shipping is “repl...
2009-12-14
288 reads
The Denver Tech Trifecta is set for February 27, 2010 at Metro State College in downtown Denver. If you are...
2009-12-14
446 reads
Tally (or numbers) tables are one of my favorite query writing tools. Such a simple premise that can be applied...
2009-12-14
3,035 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
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Comments posted to this topic are about the item SSRS Reminded Me of the...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers