SQL Server – CTP is now available for SQL Server 2008 Service Pack 3
CTP has been made available earlier this week for SQL Server 2008 SP3 on Download Center. Read this MSDN blog...
2011-08-25
736 reads
CTP has been made available earlier this week for SQL Server 2008 SP3 on Download Center. Read this MSDN blog...
2011-08-25
736 reads
sp_help returns information about database objects and types.
@object_name argument is optional for sp_help. When executed without any argument it returns...
2011-08-24
2,490 reads
You can browse available SQL Instances on network by choosing "<Browse for More..>" from Server Name drop-down list in "Connect...
2011-08-23
2,087 reads
sys.dm_db_persisted_sku_features lists all features which are utilized by the database. Features specific to Enterprise/Developer edition are:
- Compression,
- Partitioning,
- TDE and...
2011-08-22
1,362 reads
PERCENT_RANK() returns the position of a row within the result set. In contrast to RANK() function, PERCENT_RANK() ranks rows between...
2011-08-19
1,044 reads
CUME_DIST() calculates relative position of a value relative to a group of values. The value returned by CUME_DIST() is > 0...
2011-08-18
660 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers