Rebuild all the Indexes of a SQL Database in one go
Introduction
In my last post, I had explained what could be the best value of Fill Factor for the indexes in...
2011-06-20
5,417 reads
Introduction
In my last post, I had explained what could be the best value of Fill Factor for the indexes in...
2011-06-20
5,417 reads
Introduction
When an index is created or rebuilt, the fill-factor value determines the percentage of space on each leaf-level page to...
2011-06-13
7,464 reads
In my last blog about Tally Tables, we talked about the use of
recursive CTEs to generate Tally Tables. Following that,...
2011-06-04
20,283 reads
Introduction
We have always
been wondering on how to protect/secure our t-sql code written in Stored
Procedures and UDF in shared hosting environment...
2011-05-31
13,206 reads
Introduction
The
most awaited feature has arrived - "Table-Valued parameters in SQL Server
2008". Here, I would discuss on how to use this new...
2011-03-12
4,522 reads
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
By DesertDBA
I haven’t posted in a while (well, not here at least since I’ve been...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
Comments posted to this topic are about the item The Read Committed Snapshot Isolation...
Comments posted to this topic are about the item Working with JSON/JSONB Data in...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers