2014-09-26
3 reads
2014-09-26
3 reads
In this session, Prakash will walk you through design considerations, accompanied with a script demo using PowerShell to generate a...
2014-09-26
624 reads
2014-09-19
3 reads
In this session Prakash will walk through the process he has implemented to alleviates many of the pain points for...
2014-09-19
649 reads
2014-09-19
3 reads
In this session Prakash will walk through the process he has implemented to alleviates many of the pain points for...
2014-06-30
1,067 reads
2014-06-30
2 reads
2014-06-30
1 reads
2014-06-30
2 reads
The San Francisco SQL Server User Group – June 11 2014 Uploading presentation DAC for Today’s session….
2014-06-12
625 reads
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
By DesertDBA
I haven’t posted in a while (well, not here at least since I’ve been...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
Comments posted to this topic are about the item The Read Committed Snapshot Isolation...
Comments posted to this topic are about the item Working with JSON/JSONB Data in...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers