Klaus Aschenbrenner

Klaus Aschenbrenner provides independent SQL Server Consulting Services across Europe and the US. Klaus works with the
.NET Framework and especially with the SQL Server 2005/2008 from the very beginnings. In the years 2004 - 2005 Klaus
was entitled with the MVP award from Microsoft for his tremendous support in the .NET Community. Klaus has also
written the book Pro SQL Server 2008 Service Broker which was published by Apress in the Summer of 2008. Further
information about Klaus you can find on his homepage at http://www.SQLpassion.at. He also twitters at
http://twitter.com/Aschenbrenner.

Blogs

Data-driven vs. Data-informed: Let’s Acknowledge the Truth

By

This comic was retweeted into my timeline on Twitter (I refuse to call it...

Writing Parquet Files – #SQLNewBlogger

By

Recently I’ve been looking at archiving some data at SQL Saturday, possibly querying it,...

A word about IT/cybersecurity and mental health

By

Just as it's important to take care of our physical health (and I'm guilty...

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Forums

Can you connect Power Apps to SQL Server if you work in the government?

By JJ B

My agency has been using the combo of on-premises SQL Server for the back...

Unable to connect to SQL 2019 using Pyodbc

By yyang5823

Development Environment I am learning how to use pyodbc and accessing database in SQL...

Multiple deadlocks occurring with contentious code

By zoggling

We are seeing multiple frequent deadlocks occurring with the following extract of code, which...

Visit the forum

Question of the Day

Multiple Query Trace Flags

I want to enable two trace flags, 4199 and 4137, for a single query. How should I do this:

-- A
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199, 4137);

-- B
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199, QUERYTRACEON 4137);

-- C
SELECT
  a.AddressID
, a.AddressLine1
, a.AddressLine2
, a.City
, a.StateProvinceID
, a.PostalCode
, p.FirstName
, p.LastName
FROM
  Person.Address a
  INNER JOIN person.Person AS p
    ON p.rowguid = a.rowguid
WHERE
  City           = 'SEATTLE'
  AND PostalCode = 98104
OPTION (QUERYTRACEON 4199), (QUERYTRACEON 4137);

See possible answers