Kenneth Fisher

My name is Kenneth Fisher and I am Senior DBA for a large (multi-national) insurance company. I have been working with databases for over 20 years starting with Clarion and Foxpro. I’ve been working with SQL Server for 12 years but have only really started “studying” the subject for the last 3. I don’t have any real "specialities" but I enjoy trouble shooting and teaching. Thus far I’ve earned by MCITP Database Administrator 2008, MCTS Database Administrator 2005, and MCTS Database Developer 2008. I’m currently studying for my MCITP Database Developer 2008 and should start in on the 2012 exams next year. My blog is at https://sqlstudies.com/.

All authors

All authors

Blogs

The Book of Redgate: Profits

By

Redgate is a for-profit company. We look to make money by building and selling...

Session Materials for Techorama & DataGrillen 2026

By

I’ve uploaded the slides for my Techorama session Microsoft Fabric for Dummies and my...

Stop Using Pandas for Aggregations — Try DuckDB Instead

By

If you've ever loaded a 2 GB CSV into pandas just to run a...

Read the latest Blogs

Forums

Even When You Know What You're Doing, You Can Screw Up

By Grant Fritchey

Comments posted to this topic are about the item Even When You Know What...

The New Software Team

By Steve Jones - SSC Editor

Comments posted to this topic are about the item The New Software Team

Database Mail in SQL Server 2022

By Abdellateef Ibrahim

Comments posted to this topic are about the item Database Mail in SQL Server...

Visit the forum

Question of the Day

The string_agg function

We create the following table and then insert some records in it: 

create table t1 (
   id int primary key,
   category char(1) not null,
   product varchar(50)
);

insert into t1 values
(1, 'A', 'Product 1'),
(2, 'A', 'Product 2'),
(3, 'A', 'Product 3'),
(4, 'B', 'Product 4'),
(5, 'B', 'Product 5');
What happens if we execute the following query in both Sql Server and PostgreSQL? 
select id, 
category, 
string_agg(product, ';')
                 over (partition by category order by id
                 rows between unbounded preceding and unbounded following) as stragg
from t1;

See possible answers