T-SQL Tuesday #050 – Automation
In my developer life, my motto was ‘Automate all the things’ and since transitioning to a DBA role, my motto...
2014-01-14
617 reads
In my developer life, my motto was ‘Automate all the things’ and since transitioning to a DBA role, my motto...
2014-01-14
617 reads
T-SQL Tuesday is a recurring blog party, that is started by Adam Machanic (Blog | @AdamMachanic). Each month a blog will...
2013-11-12
539 reads
Since my presentation at Orlando SQL Saturday seemed to go well (standing room only, all positive feedback) I submitted to...
2013-11-11
512 reads
As a DBA your job is to protect the data, whether that be from corruption, attack, developers or any other...
2013-11-07
524 reads
So it is done, it being my first presentation at a professional event. As you may recall, I recently presented...
2013-09-18
314 reads
I’ve submitted presentations before to CodeCamp and SQL Saturdays before, but have never been selected to present due to terrible...
2013-07-21
283 reads
Watching my career progression over the last year, an outside observer would think that I’m playing career path hop-scotch, or...
2013-06-15
540 reads
Just recently I was part of an online presentation in which the intended audience was unable to install any of...
2013-04-04
230 reads
One method my company deploys our software is in a dedicated hosted environment. In this situation, we partner with a...
2013-03-28
1,164 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers