Book Review: SQL Server 2008 Query Performance Tuning Distilled
I recently finished reading the Apress book SQL Server 2008 Performance Tuning Distilled by Grant Fritchey and Sajal Dam. I...
2010-01-07
1,337 reads
I recently finished reading the Apress book SQL Server 2008 Performance Tuning Distilled by Grant Fritchey and Sajal Dam. I...
2010-01-07
1,337 reads
2010-01-04
755 reads
Well, I set 7 professional goals for 2009 and I did okay in meeting them, but I was not successful...
2009-12-31
1,381 reads
I recently had the opportunity to present, Nuggets Found by Mining the Default Trace, for SQLLunch. This was my first...
2009-12-28
339 reads
Merry Christmas to everyone. As many of you know, at least I hope you do, I am a born-again Christian...
2009-12-24
348 reads
I just found out that I’ve been accepted to speak at SQLSaturday #32 – Tampa on January 23, 2010. My session...
2009-12-23
365 reads
I did my first SQLLunch today and it was fun. I don’t know how many attended, my last look was...
2009-12-21
345 reads
I know you all are clamoring for the opportunity to have lunch with me so I agreed to do a...
2009-12-18
337 reads
The Reported Problem
A few weeks ago I was contacted by a former employer because an SSRS report I had written...
2009-12-17
398 reads
I was tagged by Ken Simmons (@kensimmons) in the blog chain started by David Stein (@made2mentor). Here’s Ken’s post and...
2009-12-14
502 reads
Setting page visibility and the active page are often overlooked last steps when publishing...
By Steve Jones
It’s time for T-SQL Tuesday again and this time Todd Kleinhans has a great...
By Steve Jones
Recently I was working in VS Code and I saw a walkthrough for the...
Looking for a laptop on rent in Bangalore? Renting laptops is a smart choice...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers