My Conversation with Ted Kummert at the PASS 2010 Summit
For some mysterious reason, I was selected as one of the “official” bloggers/tweeters during the PASS Keynotes last week. This...
2010-11-15
614 reads
For some mysterious reason, I was selected as one of the “official” bloggers/tweeters during the PASS Keynotes last week. This...
2010-11-15
614 reads
Last week, during the first day of the PASS 2010 Summit, Microsoft’s Joe Sack announced the revamped testing program for...
2010-11-15
1,307 reads
Here is the November 2010 version of my diagnostic information queries for SQL Server 2005. Many of these queries are...
2010-11-15
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I took the plunge and bought one of the new 250GB XBox 360 and Kinect bundles for $399 at Best...
2010-11-14
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I will be presenting my session on hardware selection and sizing today at 10:15AM in Room 608 at the PASS...
2010-11-11
647 reads
Since Microsoft announced the existence of CTP1 of SQL Server Denali during Ted Kummert’s keynote address at PASS 2010 yesterday,...
2010-11-10
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One of the small mysteries of the universe that I have been pondering lately is the fact that so many...
2010-11-10
422 reads
Microsoft announced the RTM of SQL Server 2008 R2 Parallel Data Warehouse, which will be available as an appliance in...
2010-11-09
467 reads
Apparently, when I posted this a few days ago, the Windows Live Writer plug-in that I used mangled the T-SQL...
2010-11-09
1,300 reads
I will be one of the “official” bloggers during the 2010 PASS Summit, which means that I get to sit...
2010-11-09
482 reads
Programmatic Tool Calling with the Claude SDK Every morning somebody on the team runs the...
By Steve Jones
mauerbauertraurigkeit – n. inexplicable urge to push people away, even close friends whose company...
By Brian Kelley
Pinal Dave wrote up his methodology for what to do when you discover bad...
While doing some housekeeping I came across a folder containing some scripts that appear...
Comments posted to this topic are about the item Why SQL Server Database Attach...
In SQL Server 2025, I run this code:
select bit_count('A')
What is returned? See possible answers