SQL Server 2008 SP1 CU14 and SQL Server 2008 SP2 CU4 Released
Microsoft has released two new Cumulative Updates for SQL Server 2008 SP1 and SQL Server 2008 SP2. The first one...
2011-05-17
1,519 reads
Microsoft has released two new Cumulative Updates for SQL Server 2008 SP1 and SQL Server 2008 SP2. The first one...
2011-05-17
1,519 reads
Since we are in the middle of May 2011, I thought was was time to update my SQL Server 2008...
2011-05-16
632 reads
PASS has added a new feature to the session selection process for the PASS Summit 2011, which they are calling...
2011-05-11
595 reads
I will be speaking at the Colorado Springs SQL Server User’s Group, live and in person, on Wednesday, June 15,...
2011-05-09
511 reads
Today is the last day to submit session abstracts for the PASS 2011 Summit. I was lucky enough to speak...
2011-05-04
474 reads
For Day 30 of this series, (which is the last day), I am going to talk a little about RAID,...
2011-05-01
919 reads
Writing a month long series is always a lot more work than you initially expect. You would think that I...
2011-05-01
624 reads
For Day 29 of this series, I am going to talk about some of the basic things that you should...
2011-04-30
1,388 reads
For Day 28 of this series, I am going to talk a little bit about some upcoming developments in Intel...
2011-04-28
1,638 reads
For Day 27 of this series, I am going to talk a little bit about disk performance and one easy...
2011-04-27
1,314 reads
Setting page visibility and the active page are often overlooked last steps when publishing...
By Steve Jones
It’s time for T-SQL Tuesday again and this time Todd Kleinhans has a great...
By Steve Jones
Recently I was working in VS Code and I saw a walkthrough for the...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers