Autogrow bug – fixed with Denali
Recently I ran into a bug related to autogrow of the log file. Because this was the second time I...
2011-08-23
1,874 reads
Recently I ran into a bug related to autogrow of the log file. Because this was the second time I...
2011-08-23
1,874 reads
With SQL Server Denali there has been made some improvements to the OVER clause, which I wasn’t even aware of...
2011-08-16
1,454 reads
Ever since I was a web developer back in the days, server side paging has been an issues. Back then...
2011-08-09
1,726 reads
Are you tired of doing self joins, just to get the value of a column in the previus/subsequent row, or...
2011-08-02
1,718 reads
Recently I had to create a simple query to lookup a single row in a table containing ranges that do...
2011-07-26
621 reads
My colleagues and I often joke around with “If it takes less than a second, then it’s okay!”. The reason...
2011-07-19
1,467 reads
A few weeks back we wrote about a query to tell you which database is using up most CPU time....
2011-07-12
1,484 reads
All developers know, that it is very important to encapsulate code in classes and methods to be able to reuse...
2011-07-05
798 reads
We all know how easy it is to see how much CPU power is consumed by the SQL Server process,...
2011-06-28
1,668 reads
I have actually written about this subject earlier on my Danish blog (http://www.performanceduo.com/post/Index-Rebuild-progress.aspx), but last week when working on a...
2011-06-21
18,092 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers