F# Type Inference
I’m just starting to look at functional languages from an Object Oriented background. One of the first things I thought...
2015-01-23
39 reads
I’m just starting to look at functional languages from an Object Oriented background. One of the first things I thought...
2015-01-23
39 reads
I’ve been asked a few times recently how I find remote working and how well it works so I thought...
2014-10-13
42 reads
With the release of Entity Framework 6.1 the Fluent API can now be used to create indexes. It’s still pretty...
2014-06-26
145 reads
Coming from the .Net world where continuous testing is expensive on both the wallet and processing power seeing what Ruby...
2014-03-11
50 reads
3 of the 4 major browsers now support web notifications (Safari, Firefox, Chrome) and no where near enough sites are...
2014-03-01
46 reads
The following script will backup and restore a database to the same server with a different name. Tested on SQL...
2014-03-01
46 reads
I recently rewrote a small webpage in AngularJs and it was amazing how much lighter and cleaner it made the...
2013-07-30
96 reads
When you find log4net is not writing anything to your logs it can be a pain to debug as obviously...
2013-07-29
153 reads
I was recently seeing “Internal Server Error 500” when trying to make an ajax call from an ASP.Net MVC view...
2013-06-22
529 reads
There seems to be a lot of buzz around mechanical keyboard lately as more and more manufacturers have started producing...
2013-06-19
43 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers