2015-04-20
546 reads
2015-04-20
546 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-04-08 (first published: 2015-03-31)
7,682 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-04-07
881 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-03-24
712 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-03-17
805 reads
I would like to introduce a “new” blogger to you. Joshuha Owen has restarted his blog and will be covering...
2015-02-24
750 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-02-20 (first published: 2015-02-10)
7,178 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-02-12 (first published: 2015-02-03)
7,103 reads
Steve:
James recently published part 3 of his PowerShell and Windows Forms series for creating your own SQL Tools. In this...
2015-02-09 (first published: 2015-01-30)
8,494 reads
As I mentioned in my original post, Exploring Excel 2013 as Microsoft’s BI Client, I will be posting tips regularly...
2015-02-04 (first published: 2015-01-27)
8,044 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
WA:08218154393 Jl. Raya Ubud No.10, Petulu, Kecamatan Ubud, Kabupaten Gianyar, Bali 80571
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers