DR: SQL installed on new path, master restored, and SQL can't find resource database or start jobs!?!
If you ever need to perform a DR install of SQL to a new path and then restore the system...
2012-11-12
653 reads
If you ever need to perform a DR install of SQL to a new path and then restore the system...
2012-11-12
653 reads
Today we await the arrival of a 100 year storm that threatens to surge New York harbor and the Long...
2012-10-29
1,098 reads
Hey everyone,
I have been nearing this goal for some time (a few times coming within fractions) so this is somewhat...
2012-10-26
796 reads
SQL Server will not start.
You open up the ERRORLOG (...which I would only do with a text editor like gVim...
2012-10-25
1,433 reads
This is one of my most closely held DBA secrets.
Do you use PAL? You should.
Clint Huffman is a golden god...
2012-10-24
1,277 reads
Through most of my career, I believed that at some point I would be able to learn enough and master...
2012-10-23
687 reads
Log shipping is great.
It's basically the act of beginning a restore with no recovery, and then restoring logs (with no...
2012-10-22
2,141 reads
Whenever I install a standalone SQL instance (installing on a failover cluster adds a few more steps) on a x64...
2012-10-19
874 reads
Hi everyone,
So the other day on twitter in #sqlhelp and privately with some friends at Microsoft and elsewhere I had...
2012-10-18
886 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers