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I haven’t been at this blogging thing an extremely long time, and I certainly haven’t been as consistent as I’ve...
2015-03-24
707 reads
I haven’t been at this blogging thing an extremely long time, and I certainly haven’t been as consistent as I’ve...
2015-03-24
707 reads
When Fusion IO burst onto the scene in 2007, offering a PCIe card that was said to be able to...
2015-03-16 (first published: 2015-03-10)
6,038 reads
Imagine this scenario: One of your servers just crashed, and you open a ticket with Microsoft for them to perform...
2014-11-06
1,937 reads
Databases and newborns have a lot in common. They both require constant care. They both require constant monitoring. They also...
2014-10-20 (first published: 2014-10-14)
7,036 reads
A while back I had written a post about why I’m excited about Hekaton (now called ‘In-Memory OLTP’ – not sure...
2014-09-22 (first published: 2014-09-17)
8,450 reads
If you work in IT, the office becomes your second home. It’s where we make a living, and most of...
2014-03-11 (first published: 2014-02-28)
2,959 reads
In one of SQL Server Central’s recent daily newsletters, Steve Jones’s editorial was inquiring whether or not anyone has been...
2014-03-06
1,170 reads
That guy or gal over there going on and on about spindles and IOPS – that’s your SAN admin. For the...
2014-02-17 (first published: 2014-02-12)
1,632 reads
I’m just a little late to the party, but no time like the present, right? I plan to be very...
2014-02-15
638 reads
If you administer a SQL Server Reporting Services server, chances are you’ve had users complain the report manager is loading...
2013-11-07
4,539 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers