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SQL Year and Week numbers


SQL Year and Week numbers

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jennyor
jennyor
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Jeff, It worked like a charm thanks!
Jenny
Jeff Moden
Jeff Moden
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Thanks for the feedback, Jenny.

--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

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Sara_DBA-629440
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SELECT CONVERT(VARCHAR,GetDate(),112) Tongue

Sara

A ship in the harbour is safe . . . but that's not what ships were made for. BigGrin
senthilkumar.v
senthilkumar.v
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select convert(char(4),datename(yyyy,'01/01/2008'))+convert(char(2),datepart (wk,'01/01/2008'))
Jeff Moden
Jeff Moden
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Sara_DBA (8/13/2008)
SELECT CONVERT(VARCHAR,GetDate(),112) Tongue


Heh...ok, Sara... if you read Jenny's original request, tell me how your code converts the following, posted in that original request, to a date. Tongue

DECLARE @Serial CHAR(12)
SET @Serial = 'SER074400001'



--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
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Forum FAQs
Jeff Moden
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senthilkumar.v (8/13/2008)
select convert(char(4),datename(yyyy,'01/01/2008'))+convert(char(2),datepart (wk,'01/01/2008'))


Perfect... Hehe Now, try that against Jenny's original request below... Wink

DECLARE @Serial CHAR(12)
SET @Serial = 'SER074400001'



--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
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Mike Mullen
Mike Mullen
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Here is an example that will compensate for the day of the week for Jan 1 of the year in question to make sure the result date is a Monday.

DECLARE @Serial CHAR(12)
SET @Serial = 'SER074400001'
--------------------------------------------------------------------
-- Set date for Monday of the Week
-- Compute days = week * 7 - 5
-- Have to allow for weekday of first of the year in calculation.
--------------------------------------------------------------------
select dateadd(day,
(convert(int,substring(@Serial,6,2)) * 7) - 5
- datepart(weekday,convert(datetime,('01/01/'+ substring(@Serial,4,2)))),
convert(datetime,('01/01/'+ substring(@Serial,4,2))))
Jeff Moden
Jeff Moden
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Since Day "0" was a Monday, I believe you'll find that the code I made also compensates for Monday. Smile

--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
How to post performance problems
Forum FAQs
Mike Mullen
Mike Mullen
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For the specified serial number which includes the string representing year 2007 and week 44, both solutions return a date that falls on a Monday. The first solutioin returns '11/05/07' and the second returns '10/29/07'. When these dates are converted back to the week number, the first is Monday of week 45 and the second is Monday of week 44.

set nocount on
DECLARE @Serial CHAR(12)
SET @Serial = 'SER074400001'

SELECT DATEADD(wk,DATEDIFF(wk,0,DATEADD(yy,CAST(SUBSTRING(@Serial,4,2) AS INT),'2000'))+CAST(SUBSTRING(@Serial,6,2)AS INT),0)
go

DECLARE @Serial CHAR(12)
SET @Serial = 'SER074400001'
--------------------------------------------------------------------
-- Set date for Monday of the Week
-- Compute days = week * 7 - 5
-- Have to allow for weekday of first of the year in calculation.
--------------------------------------------------------------------
select dateadd(day,
(convert(int,substring(@Serial,6,2)) * 7) - 5
- datepart(weekday,convert(datetime,('01/01/'+ substring(@Serial,4,2)))),
convert(datetime,('01/01/'+ substring(@Serial,4,2))))
go

select datepart(week,'2007-11-05') 'Week', datepart(weekday,'2007-11-05') 'Week Day'

select datepart(week,'2007-10-29') 'Week', datepart(weekday,'2007-10-29') 'Week Day'
arthur.teter
arthur.teter
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Points: 1201 Visits: 126
Little late, but I was looking for something else and saw this one today. I run across this all the time, and was wondering why something like the following wasn't suggested. it returns an integer, but formats the same for output, and can be used for sorting.

DECLARE @MyDate datetime = '1/1/2008'

select DATEPART(year, @MyDate) * 100 + DATEPART(MONTH, @MyDate)
Go


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