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extracting column values when a part of the column value is known


extracting column values when a part of the column value is known

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t.mounika01
t.mounika01
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hi
How can we extract a column values from database if we know a part of that column value.
For ex: if I have values for a column called statements like this:
(I am good Gal)
(you are a good boy) and so on..
and I want to extract all the statements that have a part called 'good'

what is the best way to query this?
Eirikur Eiriksson
Eirikur Eiriksson
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Quick thought, use the LIKE operator
Cool

USE tempdb;
GO

DECLARE @TEST TABLE
(
TEST_ID INT IDENTITY(1,1) NOT NULL PRIMARY KEY CLUSTERED
,TEST_STRING VARCHAR(50) NOT NULL
);

INSERT INTO @TEST(TEST_STRING)
VALUES
('I am a bad Gal')
,('I am a good Gal')
,('This is an old horse')
,('This is a good horse')
,('I am a good boy')
,('I am a naugthy boy');

SELECT
*
FROM @TEST T
WHERE T.TEST_STRING LIKE '%good%';



Results
TEST_ID     TEST_STRING
----------- ---------------------
2 I am a good Gal
4 This is a good horse
5 I am a good boy

t.mounika01
t.mounika01
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What to do if we want to replace the word 'good' with 'bad' in all those sentences?
I wrote it like this:
REPLACE(columnname,'good','bad')

Is there any other way to do this?
Ed Wagner
Ed Wagner
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Using the REPLACE function is the simplest way to do it. Assuming there aren't any unusual requirements, that's exactly the way I'd do it.


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t.mounika01
t.mounika01
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Thank you all for the help :-)
Luis Cazares
Luis Cazares
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Note that you might replace strings you don't want them to be replaced.


INSERT INTO @TEST(TEST_STRING)
VALUES
('I am a bad Gal')
,('I am a good Gal')
,('Oh my goodness! There''s no more goodwill')
,('He''s a patient with Osgood–Schlatter disease');

SELECT
*, REPLACE(TEST_STRING, 'good', 'bad')
FROM @TEST T
WHERE T.TEST_STRING LIKE '%good%';




Luis C.
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Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?


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Eirikur Eiriksson
Eirikur Eiriksson
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Luis Cazares (8/22/2014)
Note that you might replace strings you don't want them to be replaced.


INSERT INTO @TEST(TEST_STRING)
VALUES
('I am a bad Gal')
,('I am a good Gal')
,('Oh my goodness! There''s no more goodwill')
,('He''s a patient with Osgood–Schlatter disease');

SELECT
*, REPLACE(TEST_STRING, 'good', 'bad')
FROM @TEST T
WHERE T.TEST_STRING LIKE '%good%';



DECLARE @STR VARCHAR(50) = 'That an absolute @£$%'
SELECT REPLACE(REPLACE(REPLACE(REPLACE(@STR,'e @','ly'),'£',' a '),'$','brilliant'),'%',' point!')


Cool
Go


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