## Working of the function

 Author Message VSSGeorge SSCrazy Group: General Forum Members Points: 2053 Visits: 1578 I have an existing function on my DB which is used for date manipulations.Please explain how this function works. `ALTER FUNCTION [dbo].[ExplodeDates](@startdate datetime, @enddate datetime)returns table asreturn (with N0 as (SELECT 1 as n UNION ALL SELECT 1),N1 as (SELECT 1 as n FROM N0 t1, N0 t2),N2 as (SELECT 1 as n FROM N1 t1, N1 t2),N3 as (SELECT 1 as n FROM N2 t1, N2 t2),N4 as (SELECT 1 as n FROM N3 t1, N3 t2),N5 as (SELECT 1 as n FROM N4 t1, N4 t2),N6 as (SELECT 1 as n FROM N5 t1, N5 t2),nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N6)SELECT DATEADD(day,num-1,@startdate) as thedateFROM numsWHERE num <= DATEDIFF(day,@startdate,@enddate) + 1` twin.devil SSCertifiable Group: General Forum Members Points: 5086 Visits: 2692 This function is using Tally Table approach to generate calendar date between the @startDate And @EndDateif you want to understand properly then using this post from Stefan Krzywicki "Tally Table Uses - Part I" http://www.sqlservercentral.com/articles/Tally+Table/70735/ ChrisM@Work SSC-Dedicated Group: General Forum Members Points: 39082 Visits: 19989 Run the following code, query by query. If you're still unsure, post back.`WITH N0 as (SELECT 1 as n UNION ALL SELECT 1) -- 2 rows,N1 as (SELECT 1 as n FROM N0 t1, N0 t2) -- 4 rowsSELECT * FROM N1;WITH N0 as (SELECT 1 as n UNION ALL SELECT 1) -- 2 rows,N1 as (SELECT 1 as n FROM N0 t1, N0 t2) -- 4 rowsSELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) as num FROM N1;WITH N0 as (SELECT 1 as n UNION ALL SELECT 1) -- 2 rows,N1 as (SELECT 1 as n FROM N0 t1, N0 t2) -- 4 rows,nums AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) as num FROM N1)SELECT DATEADD(day,num, GETDATE()) FROM nums;` “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps ChrisM@Work SSC-Dedicated Group: General Forum Members Points: 39082 Visits: 19989 Note that you don't need CTE N6:`DECLARE @startdate DATE, @enddate DATESET @startdate = '00010101'SET @enddate = '99990101';with N0 as (SELECT 1 as n UNION ALL SELECT 1) -- 2 rows,N1 as (SELECT 1 as n FROM N0 t1, N0 t2) -- 4 rows,N2 as (SELECT 1 as n FROM N1 t1, N1 t2) -- 16 rows,N3 as (SELECT 1 as n FROM N2 t1, N2 t2) -- 256 rows,N4 as (SELECT 1 as n FROM N3 t1, N3 t2) -- 65,536 rows,N5 as (SELECT 1 as n FROM N4 t1, N4 t2) -- 4,294,967,296 rows--,N6 as (SELECT 1 as n FROM N5 t1, N5 t2) -- 18,446,744,073,709,551,616 rows!!,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N5)SELECT DATEADD(day,num-1,@startdate) as thedateFROM numsWHERE num <= DATEDIFF(day, @startdate, @enddate) + 1` “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps Jeff Moden SSC Guru Group: General Forum Members Points: 202775 Visits: 41943 Not that many people would notice but you can get the code to be almost a third faster by eliminating the (-1) subtraction. Last but not least, the simplification actually instills a guarantee that you won't have an accidental overrun sometimes caused by the very rare but annoying delay as to when the WHERE clause is executed when you join the results of this function in an external query (Itzik Ben-Gan published that correction to his code just a couple of days after he first published the cascading CTE method used here).` CREATE FUNCTION dbo.ExplodeDates ( @pStartDate DATETIME ,@pEndDate DATETIME )RETURNS TABLE WITH SCHEMABINDING AS RETURN WITH E1(N) AS ( SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 ), E7(N) AS (SELECT 1 FROM E1 a, E1 b, E1 c, E1 d, E1 e, E1 f, E1 g) SELECT TheDate = @pStartDate UNION ALL --This eliminates the need for subtraction on the Row_Number SELECT TOP (DATEDIFF(dd,@pStartDate,@pEndDate)) --and addition here TheDate = DATEADD(dd,ROW_NUMBER() OVER (ORDER BY (SELECT NULL)),@pStartDate) FROM E7;` --Jeff ModenRBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair Helpful Links:How to post code problemsHow to post performance problemsForum FAQs ChrisM@Work SSC-Dedicated Group: General Forum Members Points: 39082 Visits: 19989 Jeff Moden (11/29/2013)Not that many people would notice but you can get the code to be almost a third faster by eliminating the (-1) subtraction. Last but not least, the simplification actually instills a guarantee that you won't have an accidental overrun sometimes caused by the very rare but annoying delay as to when the WHERE clause is executed when you join the results of this function in an external query (Itzik Ben-Gan published that correction to his code just a couple of days after he first published the cascading CTE method used here).` CREATE FUNCTION dbo.ExplodeDates ( @pStartDate DATETIME ,@pEndDate DATETIME )RETURNS TABLE WITH SCHEMABINDING AS RETURN WITH E1(N) AS ( SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 ), E7(N) AS (SELECT 1 FROM E1 a, E1 b, E1 c, E1 d, E1 e, E1 f, E1 g) SELECT TheDate = @pStartDate UNION ALL --This eliminates the need for subtraction on the Row_Number SELECT TOP (DATEDIFF(dd,@pStartDate,@pEndDate)) --and addition here TheDate = DATEADD(dd,ROW_NUMBER() OVER (ORDER BY (SELECT NULL)),@pStartDate) FROM E7;`How are you demonstrating the difference, Jeff? The results of a quick test show the opposite, but not by very much:`DECLARE @startdate DATE, @enddate DATE, @Blackhole DATE;SET @startdate = '00010101'SET @enddate = '99991231';PRINT '==Slow inline tally table==';PRINT CHAR(10)+'--Subtraction--';SET STATISTICS TIME ON;with N0 as (SELECT 1 as n UNION ALL SELECT 1) -- 2 rows,N1 as (SELECT 1 as n FROM N0 t1, N0 t2) -- 4 rows,N2 as (SELECT 1 as n FROM N1 t1, N1 t2) -- 16 rows,N3 as (SELECT 1 as n FROM N2 t1, N2 t2) -- 256 rows,N4 as (SELECT 1 as n FROM N3 t1, N3 t2) -- 65,536 rows,N5 as (SELECT 1 as n FROM N4 t1, N4 t2) -- 4,294,967,296 rows,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N5)SELECT @Blackhole = thedate FROM ( SELECT thedate = DATEADD(day,num-1,@startdate) FROM nums WHERE num <= DATEDIFF(day, @startdate, @enddate) + 1) d;SET STATISTICS TIME OFF;PRINT CHAR(10)+'--UNION--';SET STATISTICS TIME ON;with N0 as (SELECT 1 as n UNION ALL SELECT 1) -- 2 rows,N1 as (SELECT 1 as n FROM N0 t1, N0 t2) -- 4 rows,N2 as (SELECT 1 as n FROM N1 t1, N1 t2) -- 16 rows,N3 as (SELECT 1 as n FROM N2 t1, N2 t2) -- 256 rows,N4 as (SELECT 1 as n FROM N3 t1, N3 t2) -- 65,536 rows,N5 as (SELECT 1 as n FROM N4 t1, N4 t2) -- 4,294,967,296 rows,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N5)SELECT @Blackhole = thedate FROM ( SELECT thedate = @startdate UNION ALL SELECT DATEADD(day,num,@startdate) FROM nums WHERE num <= DATEDIFF(day, @startdate, @enddate)) d;SET STATISTICS TIME OFF;PRINT CHAR(10)+CHAR(10)+'==Fast IBG inline tally table==';PRINT CHAR(10)+'--Subtraction--';SET STATISTICS TIME ON;WITH E1(N) AS ( SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 ), E7(N) AS (SELECT 1 FROM E1 a, E1 b, E1 c, E1 d, E1 e, E1 f, E1 g)SELECT @Blackhole = thedate FROM ( SELECT TOP (1+DATEDIFF(dd,@StartDate,@EndDate)) TheDate = DATEADD(dd,ROW_NUMBER() OVER (ORDER BY (SELECT NULL))-1,@StartDate) FROM E7) d;SET STATISTICS TIME OFF;PRINT CHAR(10)+'--UNION--';SET STATISTICS TIME ON;WITH E1(N) AS ( SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 ), E7(N) AS (SELECT 1 FROM E1 a, E1 b, E1 c, E1 d, E1 e, E1 f, E1 g)SELECT @Blackhole = thedate FROM ( SELECT TheDate = @StartDate UNION ALL --This eliminates the need for subtraction on the Row_Number SELECT TOP (DATEDIFF(dd,@StartDate,@EndDate)) --and addition here TheDate = DATEADD(dd,ROW_NUMBER() OVER (ORDER BY (SELECT NULL)),@StartDate) FROM E7) d;SET STATISTICS TIME OFF;PRINT '=================================================================================';` “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps