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Parsing Last,First Middle Name


Parsing Last,First Middle Name

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ajlefort
ajlefort
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Group: General Forum Members
Points: 3 Visits: 3
Hi,
I need to parse last name,first name space middle name.
Example A - DOE,JOHN
Example B - DOE,JOHN A

I am able to parse the last name.
left(dbo.AbstractData.Name, charindex(',', dbo.AbstractData.Name)-1) as last name

I can parse the first and middle names together.
ltrim(right( dbo.AbstractData.Name,(len(dbo.AbstractData.Name)-charindex(',',dbo.AbstractData.Name))))
as firstmiddlename

I can parse the middle name.
SUBSTRING(dbo.AbstractData.Name,CHARINDEX(' ',dbo.AbstractData.Name + ' ')+1,LEN(dbo.AbstractData.Name))

I am having trouble parsing the first name. The first name is everything after the comma and before the first blank after the comma (or the end of the string, in which case there is no middle name).
Can anyone help me parse the first name only?

Thanks
Sean Lange
Sean Lange
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Group: General Forum Members
Points: 16566 Visits: 17016
Not 100% certain what you are after here but take a look at this. This will parse everything into last, first, middle.


if OBJECT_ID('tempdb..#Something') is not null
drop table #Something

create table #Something
(
SomeID int identity,
FullName varchar(25)
)

insert #Something
select 'DOE,JOHN' union all
select 'DOE,JOHN A'

select *
from #Something
cross apply dbo.DelimitedSplit8K(replace(FullName, ' ', ','), ',') p



You can find the code for the DelimitedSplit8K function by following the link in my signature about splitting strings.

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Luis Cazares
Luis Cazares
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Group: General Forum Members
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If you ever cross with a spanish last name with spaces, you might have problems with the 8K splitter.
This formula might have its own problems, but it's another option for you.


if OBJECT_ID('tempdb..#Something') is not null
drop table #Something

create table #Something
(
SomeID int identity,
FullName varchar(25)
)

insert #Something
select 'DOE,JOHN' union all
select 'DOE,JOHN A' union all
select 'DE LA VEGA,ELENA'

SELECT SUBSTRING( FullName, CHARINDEX(',', FullName) + 1, ISNULL(NULLIF(CHARINDEX(' ', FullName, CHARINDEX(',', FullName)), 0), 8000) - (CHARINDEX(',', FullName) + 1))
,CHARINDEX(',', FullName) + 1
,ISNULL(NULLIF(CHARINDEX(' ', FullName, CHARINDEX(',', FullName)), 0), 8000) - (CHARINDEX(',', FullName) + 1)
FROM #Something




Luis C.
General Disclaimer:
Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?


How to post data/code on a forum to get the best help: Option 1 / Option 2
sqldriver
sqldriver
Mr or Mrs. 500
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Group: General Forum Members
Points: 586 Visits: 2492
This isn't precisely what you're trying to do, but I found it helpful when trying to do some similar parsing. There's a lot you have to look out for.

http://www.informit.com/articles/article.aspx?p=25049
Steven Willis
Steven Willis
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Group: General Forum Members
Points: 477 Visits: 1721
Take a look at the procedure in this post:

http://www.sqlservercentral.com/Forums/FindPost1472808.aspx


 
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