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Arithmetic 1


Arithmetic 1

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bitbucket-25253
bitbucket-25253
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Comments posted to this topic are about the item Arithmetic 1

If everything seems to be going well, you have obviously overlooked something.

Ron

Please help us, help you -before posting a question please read

Before posting a performance problem please read
baabhu
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Good Question. Back to the basics. +1 to the total.
PRAMANA.DBA
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Good Question....
Michael Riemer
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Very interesting question. Learnt something new again.
sqldoubleg
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The explanation I see is that on answers 1,3,4,5,6 implicit data types conversion happens because of mixing INT and CHAR types.

On the answer 2, we just try to multiply 2 CHAR, therefore an error is raised up.

Good question!
Christy M
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raulggonzalez (2/29/2012)
The explanation I see is that on answers 1,3,4,5,6 implicit data types conversion happens because of mixing INT and CHAR types.

On the answer 2, we just try to multiply 2 CHAR, therefore an error is raised up.

Good question!
Yeah, I have to agree, multiplying strings is the cause. It errors before it even tries to implicitly cast the answer to an int.
Steve Hall
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I particularly like the fact that a QOTD was verified by several people before publication.

Steve Hall
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Raghavendra Mudugal
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It gives me this error on the 2nd block

Msg 8117, Level 16, State 1, Line 3
Operand data type char is invalid for multiply operator.

I guess E stands for ERROR?

ww; Raghu
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The first and the hardest SQL statement I have wrote- "select * from customers" - and I was happy and felt smart.
Carlo Romagnano
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This kind of error also is independent from version of sqlserver.
You can not use - * / operators with chars
Toreador
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Yet another question that tells us not to rely on implicit conversion...
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