ChrisM@Work (12/2/2013)

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Here's the simplest way. Without further information it's unlikely to be the best.

-- I have an Employee table with Columns:

DROP TABLE #Employee

CREATE TABLE #Employee (EmpID INT IDENTITY(1,1), FirstName VARCHAR(100), MiddleName VARCHAR(100), LastName VARCHAR(100),

SSN VARCHAR(25), BirthDate DATE, HireDate DATE, City VARCHAR(100), Zip VARCHAR(10))

INSERT INTO #Employee (FirstName, MiddleName, LastName, SSN, BirthDate, HireDate, City, Zip)

SELECT 'John', NULL, 'Smith', 'Smooth bitter', GETDATE(), GETDATE(), 'London', 'W1' UNION ALL

SELECT 'Timothy', NULL, 'Taylor', 'Landlord', GETDATE(), GETDATE(), 'London', 'W1' UNION ALL

SELECT 'Timothy', NULL, 'Taylor', 'Y', GETDATE()+1, GETDATE()+1, 'London', 'W1' UNION ALL

SELECT 'Timothy', NULL, 'Taylor', 'X', GETDATE(), GETDATE(), 'P', 'Q' UNION ALL

SELECT 'X', NULL, 'Y', 'Landlord', GETDATE(), GETDATE(), 'Z', 'A'

-- Requirement: I have to identify the duplicate records based on below criteria:

SELECT

EmpID, FirstName, MiddleName, LastName, SSN, BirthDate, HireDate, City, Zip,

Criteria1, Criteria2, Criteria3

FROM (

SELECT

EmpID, FirstName, MiddleName, LastName, SSN, BirthDate, HireDate, City, Zip,

Criteria1 = COUNT(*) OVER(PARTITION BY SSN),

Criteria2 = COUNT(*) OVER(PARTITION BY FirstName, LastName, BirthDate),

Criteria3 = COUNT(*) OVER(PARTITION BY FirstName, LastName, City, Zip)

FROM #Employee

) d

WHERE Criteria1+Criteria2+Criteria3 > 3