November 11, 2013 at 7:59 am
Hi,
We have 2 node cluster in windows server 2003, sql server 2000. Drives are allocated from net app. When the disk in cluster gets full, whole cluster goes down. Anybody faced similar issue before? Any idea how disk full takes the disk offline?
Ryan
//All our dreams can come true, if we have the courage to pursue them//
November 11, 2013 at 8:05 am
at the Netapp filer level if the LUN space depletes the LUN goes offline, this in turn will take the disk offline in Windows.
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"Ya can't make an omelette without breaking just a few eggs" 😉
November 11, 2013 at 8:15 am
Thanks Perry
But disk might get full due to huge transactions. So to prevent this, is there anything that can be done so that LUN does not go offline if the disk goes full like kind of creating reserve space in LUN or anything else.
Please advice.
Ryan
//All our dreams can come true, if we have the courage to pursue them//
November 11, 2013 at 10:16 am
Ryan007 (11/11/2013)
Thanks PerryBut disk might get full due to huge transactions. So to prevent this, is there anything that can be done so that LUN does not go offline if the disk goes full like kind of creating reserve space in LUN or anything else.
Please advice.
Increase your lun size, sounds like it needs it!
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"Ya can't make an omelette without breaking just a few eggs" 😉
November 11, 2013 at 12:01 pm
A short term solution might be to configure maximum data and log files sizes to the disk can't fill up. You'll still have problems, but at least the cluster won't go down and you can address them.
November 11, 2013 at 2:16 pm
Ryan007 (11/11/2013)
Thanks Perry[font="Arial Black"]But disk might get full due to huge transactions[/font]. So to prevent this, is there anything that can be done so that LUN does not go offline if the disk goes full like kind of creating reserve space in LUN or anything else.
Please advice.
You have correctly identified the problem. I recommend you check the code that does that and find out why.
--Jeff Moden
Change is inevitable... Change for the better is not.
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