GilaMonster (7/2/2015)

---

yb751 (7/2/2015)

---

--When you want to do this

SET @query_from = @query_from + CHAR(10) + ' JOIN ' + @TableVariable + ' on ABC.ID = ' + @TableVariable + '.ID...

It becomes much simpler to visualize what you are doing wrong when you output your string.

DECLARE @TableVariable NVARCHAR(50) = 'MyTable'

DECLARE @query_from NVARCHAR(MAX) = ''

---You are doing this

SET @query_from = @query_from...

SQLBill (6/26/2015)

---

For the author....his delay in getting the rest of the series out means the GoT show will probably finish and then everyone will compare his books to the show....

TCcool (6/26/2015)

---

To create a table that houses all the patterns would take much too long. The rows in the actual tables are in the millions and I am looking for...

TCcool (6/26/2015)

---

Thank you for posting the code formatted correctly - do you, by chance, have a link to the formatting code for this forum regarding "How-To", so that I can...

Here's what I came up with. You'll have to populate a table with your search patterns.

DECLARE @people TABLE (Logid INT IDENTITY(1,1), SourceData NVARCHAR(50), Account NVARCHAR(50))

DECLARE @check TABLE (Pattern NVARCHAR(10))

INSERT...

Since your using 2005...

DECLARE @people TABLE (Logid INT IDENTITY(1,1), SourceData NVARCHAR(50), Account NVARCHAR(50))

INSERT INTO @people (SourceData, Account)

SELECT '123X-456','56789' UNION ALL

SELECT '456/123','A345' UNION ALL

SELECT 'ABC 345','X567' UNION ALL

SELECT '456 HELP-123','YCHB' UNION...

SQLBill (6/25/2015)

---

Brandie Tarvin (6/25/2015)

---

So... at risk of alienating a potential fan base for my own ensemble-cast novel-in-progress.

Why did you hate his books (aside from him killing off favorite characters)?

Was it...

Kutang Pan (6/25/2015)

---

My Solution:

SELECT A.ID,COUNT(B.SomeColumn) AS [CountOfB]

FROM @T1 A

LEFT JOIN @T2 B ON B.SomeColumn = A.ID

LEFT JOIN @T2 B2 ON B2.AnotherC = A.ID

GROUP BY A.ID

That should perform better and...

CraigIW (6/25/2015)

---

The real joins actually have four other parts. It seemed unrealistic to post the entire schema and would have taken an age to anonymise.

The originally suggested solution appears to...

EDIT: Sorry I just wasn't happy with my original solution.

lskidgel (6/24/2015)

---

I should probably clarify; the 1st table will display 5 rows of data, and the 2nd table will also display rows of data, although the # of rows...

I don't know what you are using as your dataset but you could just have two sources.

I'm just using pseudo code here but something like...

SELECT TOP 5 Question, Answer FROM...

Sean Lange (6/23/2015)

---

yb751 (6/23/2015)

---

GilaMonster (6/23/2015)

---

I'll probably be looking to get new kittens/cats later this year. My Siamese died late May, completely unexpected, out of the blue. One day she was...

GilaMonster (6/23/2015)

---

I'll probably be looking to get new kittens/cats later this year. My Siamese died late May, completely unexpected, out of the blue. One day she was fine, next day...