Viewing 15 posts - 301 through 315 (of 398 total)
Here are something to check with.
Does local select makes difference? if fast, then check network.
Check query execution plan on select, setup index to see the effect. It should unless the...
March 5, 2004 at 4:24 am
select @sstring='select FDT_V_FIRECODE,FDT_V_DESC,FDT_V_COUNTY from ZCM_FDT_FIREDISTRICT where FDT_V_FIRECODE like ''%'+@fdt_v_firecode+'%'''
March 5, 2004 at 4:01 am
You need index on the table for both speed and data integrity reasons.
March 4, 2004 at 10:15 pm
Are you in SQL2000 with FULL recovery model?
March 4, 2004 at 10:03 pm
Performance can change dramaticly once a threshold has been reached.
If restart sql server help, it may relate to log file or memory leaking etc.
Also check log file growing limitation.
March 4, 2004 at 7:01 am
That comes to the same issue of none-clustered installation. You may have to clean up registry(on every node) before try it again.
March 4, 2004 at 6:51 am
You can use the existing virtual server name or if you do not like it, create another one. Both are valid options.
March 4, 2004 at 6:37 am
You may have to rebuild the registry.
It sounds like entries in HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\MSSQLServer\MSSQLServer\Parameters
are not correct.
March 4, 2004 at 6:28 am
Take the cluster resource offline, drop it and try it again.
BOL search on 'How to create a new failover cluster (Setup)'. It has step-by-step instructions.
March 4, 2004 at 6:04 am
net stop mssqlserver
net start mssqlserver
and schedule it at windows level (at command).
March 4, 2004 at 5:51 am
Most likely it uses table scan instead of indexes, that explains large tables are most effected.
Do a reindex may help.
DBCC DBReindex or DBCCIndexDefrag
March 4, 2004 at 5:47 am
Did you install the instance on existing virtual server or you created a new virtual server, then try to install sql server on the virtual server?
March 4, 2004 at 5:37 am
Somehow I feel that it would be much easy for one-one level log tracking, instead of one-many (sa_LogTable logs all changes) for the following reasons.
1. multiple columns primary key.
2. none-key table.
3.varchar length limitation.
March 4, 2004 at 5:28 am
Replace
declare @i varchar(100)
set @i = ' 1 456 9'
set @i=replace(@i,' ','')
select @i
March 3, 2004 at 8:10 pm
disk compression is one place to look at.
Thinking disk partition cluster size may also play a role.
March 3, 2004 at 7:15 pm
Viewing 15 posts - 301 through 315 (of 398 total)