Viewing 15 posts - 61 through 75 (of 122 total)
Yes dwain.c, that would work as well! Thanks for the input.
January 13, 2014 at 10:33 am
Wow!!! That is fantastic! Thank you so much!
January 10, 2014 at 8:51 am
My father is from Germany and our lastname is short on vowels. There is only one and the last three letters are consonants. People inevitably want to put...
October 28, 2013 at 8:48 am
Not sure I want to throw this out there, but here goes... I deal with some very large tables and count(*) or count(PrimaryKey) performs horribly at times. When I...
October 15, 2013 at 9:27 am
Jeff Moden (9/19/2013)
Erland Sommarskog (9/19/2013)
September 20, 2013 at 10:21 am
Wow!! Very cool! Thank you!
July 12, 2013 at 8:27 am
Correct. The query window is running only one of those. And in another query window, I'm checking the table as it runs (using sp_spaceused because it is so...
July 11, 2013 at 4:25 pm
Thank you for the very detailed explanation Craig! That is exactly what I need. That pivot query was very, VERY helpful. I was able to see how...
March 18, 2013 at 5:25 pm
Thank you for your reply Naga. Yes, it is a lot of information. I tried to be real methodical but it just made for a very long post!...
March 6, 2013 at 4:15 pm
Good question. There is another server in this whole configuration, let's call it Server 1. That's what the end users are hitting and updating. Server A copies...
February 20, 2013 at 10:44 am
Server A processes data in WarehouseDB at midnight every night. As soon as that is done, the transaction log is backed up. Server B then has a job...
February 20, 2013 at 9:34 am
GilaMonster (2/20/2013)
February 20, 2013 at 8:59 am
Dilip -
Click the link at the top (or bottom) of the article that indicates "This Article is part of the Stairway Series: Stairway to SQL Server Reporting Services." That...
December 21, 2012 at 8:56 am
Another option:
SELECT pd.CustID
FROM Product_Details pd
LEFT JOIN (SELECT CustID FROM Product_Details WHERE ProdID = 0) c ON pd.CustID = c.CustID
WHERE pd.ProdID IN (1, 4)
AND c.CustID IS NULL
GROUP BY pd.CustID
HAVING COUNT(*) =...
September 17, 2012 at 10:54 am
This is SO cool!! Someone from this distinguished community simply MUST end up in the 15 finalists!!!
October 13, 2011 at 9:12 am
Viewing 15 posts - 61 through 75 (of 122 total)