Viewing 15 posts - 4,666 through 4,680 (of 6,036 total)
I wonder why MS does not restrict altering more than one column within one month.
December 12, 2006 at 9:59 pm
I think he ment this:
SELECT *
FROM yourtable
WHERE Dep_name = 'prod'
ORDER BY Member_Name
SELECT *
FROM yourtable
WHERE...
December 12, 2006 at 8:57 pm
Debra, take a break and spend several minutes learning SQL syntax.
declare @weight varchar(20)
set @weight = 5
declare @sql varchar(8000)
set @sql = 'select [' + @weight + '] from shippingrates with (NOLOCK)'
PRINT...
December 12, 2006 at 3:41 pm
Copying images to audit table is not such a brilliant idea.
It's huge overhead which will slow down the system significantly.
But if you really sure you need to do it then...
December 12, 2006 at 2:20 pm
Problem is:
@Weight char(50),
[ + @Weight + ]
becomes
[5 ...
December 12, 2006 at 2:12 pm
To make it universal and manageable:
SELECT t.rowid, n.Number
FROM t
INNER JOIN [Numbers] n
INNER JOIN AllowedSymbols A ON n.Number = A.ASCIICode
WHERE SUBSTRING([column],n.Number,1) = A.Symbol
Table AllowedSymbols contains all symbols not to be...
December 12, 2006 at 3:17 am
> select * from tbl_ORD_CUST where c_order_id = x
It must be @x?
And what is the datatype of @x?
December 11, 2006 at 8:01 pm
Original request was :
> Can anyone suggest a quick way to create 100,000 random numbers without using a cursor or loop ?
100,000 random numbers means 100,000 numbers, not a random...
December 11, 2006 at 4:38 pm
chandrika5, to which of user records you wanna join fname2 lname2?
December 9, 2006 at 2:52 am
When you pray for long life ask nt only for yourself. Pray also for Microsoft stil to be there and support current version of MS SQL Server.
December 9, 2006 at 2:24 am
1700, 1800, 1900 were not leap years.
2100, 2200 will not be as well.
2000 was an exclusion because of "reverse compesation".
Leap year adds 6 hours to each year. Instead of 5...
December 8, 2006 at 8:54 pm
You need scalar function taking string as 1st parameter and name part as 2nd one.
Then it's gonna be like this:
Select dbo.NamePart(FullName, 'FirstName') as FirstName, dbo.NamePart(FullName, 'MiddleName') as MiddleName, dbo.NamePart(FullName, 'LastName')...
December 8, 2006 at 6:06 pm
December 8, 2006 at 4:57 pm
What are you trying to do?
Explain in normal words.
December 8, 2006 at 3:21 pm
Viewing 15 posts - 4,666 through 4,680 (of 6,036 total)