Viewing 15 posts - 11,986 through 12,000 (of 15,379 total)
Lynn Pettis (5/11/2012)
Sean Lange (5/11/2012)
Matt Miller (#4) (5/11/2012)
Lynn Pettis (5/11/2012)
Matt Miller (#4) (5/11/2012)
May 11, 2012 at 12:16 pm
This sounds a lot like homework. I would suggest that a CTE for this is not the best way to go. See this article from Wayne. http://www.sqlservercentral.com/articles/comma+separated+list/71700/%5B/url%5D
May 11, 2012 at 11:58 am
Matt Miller (#4) (5/11/2012)
Lynn Pettis (5/11/2012)
Matt Miller (#4) (5/11/2012)
May 11, 2012 at 11:50 am
Lynn Pettis (5/11/2012)
Sean Lange (5/11/2012)
Lynn, why not the replace I posted above? It is super fast because it doesn't have to do all sorts of string manipulation.
Didn't see it. ...
May 11, 2012 at 9:38 am
Oh you have a hybrid with EAV going on here. UGH!!! You really should just make the extra stuff columns in your order table and not as lookup values from...
May 11, 2012 at 9:35 am
Lynn, why not the replace I posted above? It is super fast because it doesn't have to do all sorts of string manipulation.
May 11, 2012 at 9:28 am
I think the OP wants no result set at all when there is no row. 0 row(s) returned.
May 11, 2012 at 8:57 am
What is it trying to do? This can certainly be made quite a bit simpler by the looks of it.
May 11, 2012 at 8:54 am
mark.doyle (5/10/2012)
I am reletively new to SQL and i have wrote the following basic procedure to check if a field in my table is...
May 11, 2012 at 8:51 am
Like this?
if exists
(
select 1
FROM [MantagheInfo]
WHERE (YearID = @year)
)
select
SUM(isnull([TedadTarhModiriatTafzili],0))as TedadTarhModiriatTafzili
, SUM(isnull([TedadTarhModiriatJame],0))as TedadTarhModiriatJame
, SUM(isnull([TedadKhodro],0))as TedadKhodro
, SUM(isnull([TedadMotorcycle],0))as TedadMotorcycle
, SUM(isnull([TedadGhayegh],0))as TedadGhayegh
, SUM(isnull([TedadBisim],0))as TedadBisim
, SUM(isnull([TedadDoorbinAksbardari],0))as TedadDoorbinAksbardari
, SUM(isnull([TedadDoorbinCheshmi],0))as TedadDoorbinCheshmi
FROM [MantagheInfo]
WHERE (YearID = @year)
May 11, 2012 at 8:42 am
How about nested replace. You said all you want is to remove "#" and any numbers.
SELECT rtrim(ltrim(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(REPLACE(Data, '#', ''), '1', ''), '2', ''), '3', ''), '4', ''), '5', ''), '6',...
May 11, 2012 at 8:34 am
dwain.c (5/11/2012)
Sean Lange (4/19/2012)
No loops, no cursors.
Hey, wait a minute! That's part of my mantra! :w00t:
LOL
May 11, 2012 at 8:04 am
alvirasingh2012 (5/11/2012)
these are the aggregate function.they are reduce coding and easy to use.
spam reported
May 11, 2012 at 8:02 am
alvirasingh2012 (5/11/2012)
hello dude,htis is my same problem .if u found any solution pls reply me.
spam reported
May 11, 2012 at 8:01 am
Viewing 15 posts - 11,986 through 12,000 (of 15,379 total)