Viewing 15 posts - 6,736 through 6,750 (of 15,381 total)
RVO (9/23/2013)
You really are SSChampion !!!!!
It runs in 1 sec now !!!
Wow.
I just need to understand what is the trick
and what was wrong with my old code
because I...
September 23, 2013 at 2:47 pm
GilaMonster (9/23/2013)
November it's good bye consulting, back to full time grind. Starting at a software development house as a technical lead. Focusing on...
September 23, 2013 at 2:08 pm
golansimani (9/23/2013)
UPDATE table_a
...
September 23, 2013 at 2:06 pm
Totally a shot in the dark because we don't have much in the way details...
See if this helps.
SELECT p.RollupAllProjectsCommittedTotalCost * CASE WHEN RowNum = 1 THEN 1 ELSE 0 END,...
September 23, 2013 at 1:59 pm
Based on your screen shot and the description this sounds like a search criteria based on the values the user wants to use as their criteria. This is a very...
September 23, 2013 at 1:37 pm
See if this makes things any better.
FROM
vwNzEmpNonPrjTime e
outer apply getValuesAsTable(@L_ORG, ',') o
outer apply getValuesAsTable(@L_EMPLOYEE, ',') et
WHERE
co_code = @L_CO_CODE
AND (CHARINDEX('**all**', @L_ORG) > 0 OR o.org_code = o.[SomeColumn])
AND (CHARINDEX('**all**', @L_EMPLOYEE)...
September 23, 2013 at 1:32 pm
Check out the link in my signature about splitting strings. In there you will find a way to do this very easily and fast.
Your code might be as simple as...
September 23, 2013 at 12:04 pm
stevewes (9/23/2013)
That is great info, yeah the info needs to be real time our Help desk ticketing application gets lots of email request into a particular table and seem...
September 23, 2013 at 9:15 am
ramyours2003 (9/23/2013)
September 23, 2013 at 8:46 am
stevewes (9/23/2013)
next step is to I suppose create a Job with the SQL query in as a step the next step is how...
September 23, 2013 at 8:42 am
p.avinash689 (9/23/2013)
i have to tables like patient table with columns(patient name, DOB,Age,Sex) and table2 with column (regno).
i want to insert the registration number as first 3 characters of...
September 23, 2013 at 8:34 am
Hi and welcome to the forums. In order to help we will need a few things:
1. Sample DDL in the form of CREATE TABLE statements
2. Sample data in the form...
September 23, 2013 at 8:30 am
stevewes (9/23/2013)
my select statement goes something like this
Select count(*) AS EMAILQFULL,column name from tablename
group by column name
this returns the number of rows in...
September 23, 2013 at 8:26 am
kapil_kk (9/23/2013)
Instead of this:SET @SqlQueryFirstName = '@SqlQuery ' + 'firstname = @firstname'
Write this:
SET @SqlQueryFirstName = @SqlQuery + 'firstname ='+ @firstname
Instead of this, read the article that Jeff suggested. The approach...
September 23, 2013 at 8:18 am
slpgma (9/23/2013)
September 23, 2013 at 8:12 am
Viewing 15 posts - 6,736 through 6,750 (of 15,381 total)