Viewing 15 posts - 121 through 135 (of 241 total)
Can't you look at the Snapshot Agent job? There should be Duration column.
April 11, 2014 at 9:11 am
SQL# CLR library has procedure called String_SplitIntoFields.
There other functions as well. Check it out, maybe it will help.
August 28, 2013 at 4:31 pm
Could it be ..
- Maintenance plan;
- External job scheduled in windows;
If I'm not mistaken, job history usually deleted by this procedure: sp_purge_jobhistory. Try to trace who is...
September 25, 2012 at 6:15 pm
Check agent properties. There should be a chechbox to auto remove job history.
September 25, 2012 at 1:07 am
Jeff Moden (9/23/2012)
How will any of that produce the desired output?
What is the desired output? I thought it's Account# and Quarter value next to it, No?
September 23, 2012 at 7:08 pm
You can also UNIONize quarters and then select from that union using quarter number as filter in a WHERE clause.
SELECT *
FROM (
SELECT Account, QTR1 AS QuarterValue, 1...
September 22, 2012 at 3:25 pm
Recurs1on (9/21/2012)
Query Design ...8.Do not use scalar valued functions SELECT statements
I don't think I understand this. Can you expand?
Recurs1on (9/21/2012)
9.Do not prefix search arguments in a LIKE clause...
September 21, 2012 at 9:55 pm
September 21, 2012 at 9:12 pm
I answered "Non of the above". I thought DiskIO in sp_Who2 means reads and writes combined, not just reads as question asks. Am I wrong?
September 20, 2012 at 11:16 pm
So, you need to compare TableA and TableB and only if match is found insert into TableC ? Match on what? Old and Old? New and New? Both?
How do you...
August 27, 2012 at 2:20 pm
Your SQL is full of errors. Please fix and post correct statements.
August 25, 2012 at 2:22 am
OK, I don't have time right now but here is the setup that you should have provided in your first post. Hopefully someone will help. If not, i'll take stab...
August 25, 2012 at 2:12 am
Your desired output doesn’t match the test data. Should we assume that, for example, “Arizona Alabama 788” is also in the original table?
I’m also not clear about 50 tables. Do...
August 25, 2012 at 1:17 am
demonfox (8/25/2012)
select customer , count(cust)from CustTable a
left join OrderTable
on customer=Cust
group by customer
this may have been the proper code;
why is...
August 25, 2012 at 12:46 am
cljolly (8/25/2012)
August 25, 2012 at 12:33 am
Viewing 15 posts - 121 through 135 (of 241 total)