Viewing 15 posts - 3,661 through 3,675 (of 5,103 total)
This is a looooong shot but:
Are you importing the files to SQL using a linked server ? If yes, it needs the files there ALWAYS!
* Noel
May 31, 2005 at 12:33 pm
That's happened to me a lot
... so nothing to worry about. I usually get more coffee ![]()
* Noel
May 31, 2005 at 12:24 pm
If what you are trying to avoid is a Filtering on the overall result just move that extra clause to the join like:
SELECT ISNULL (EntityPhoneNumbers.PhoneNumber, 'None')
FROM Entity
LEFT JOIN EntityPhoneNumbers ON...
* Noel
May 31, 2005 at 12:22 pm
govinn That is just a display problem;
simply change Declare @val Varchar to Declare @val Varchar (20)
and be happy ![]()
* Noel
May 31, 2005 at 12:15 pm
have you checked that Hide Server is not checked on server Network utility?
When you start the service, on the SQL Log Files, what Port number is Logged ?
* Noel
May 31, 2005 at 11:43 am
Not all numbers are representable in finite digits arithmetics you may want to try:
Declare @val Varchar
set @val = '-3.16E-05'
Select cast(cast(@val...
* Noel
May 31, 2005 at 11:36 am
I really don't understand how even the First update is affecting anything in the Table ![]()
UPDATE Table1
SET @Month = NULL
WHERE unit_id ...
@Month is a variable, Not...
* Noel
May 31, 2005 at 11:05 am
What you need is a left Join depending on the Relationships between the tables it should be something like:
Select c.Contact, Isnull(p.PhoneNo, "None") As Phone
from Contacts c Left join Phones p...
* Noel
May 31, 2005 at 10:55 am
Sorry for the delay I had to do some work ![]()
The reason for the missmatch you were getting is that AS collations consider accented...
* Noel
May 31, 2005 at 10:49 am
Sorry to keep asking but: what collation are you using ?
* Noel
May 31, 2005 at 8:47 am
Sure!
Select PID as ID from TableA where ID =x
union all
select x
* Noel
May 31, 2005 at 8:35 am
what is the datatype of the "Surname" column ?
* Noel
May 31, 2005 at 8:34 am
I don't really follow what you want. If you have two columns
all you need is:
Select ID, PID from TableA where ID =x -- This give you all PID matching that...
* Noel
May 31, 2005 at 8:28 am
usually I have found that an scoring system is the way to approach all those conditions.
It is something that has to be developed with great deal of knowledge on your...
* Noel
May 31, 2005 at 8:22 am
Viewing 15 posts - 3,661 through 3,675 (of 5,103 total)