Viewing 15 posts - 20,566 through 20,580 (of 26,484 total)
You asked for help, forum etiquette asks that you post your resolution. Others may have a similar problem and seeing how you resolved the problem may help.
June 5, 2009 at 8:28 pm
I'd also want to see the table DDL, sample data (in a readily consummable format for a cut, paste, and execute in SSMS or QA), expected results based on the...
June 5, 2009 at 6:50 pm
The first time I mentioned BOL I did spell it out, but I didn't put the TLA along with it. You'll see that if you look at my post...
June 5, 2009 at 3:43 pm
GilaMonster (6/5/2009)
Lynn Pettis (6/5/2009)
June 5, 2009 at 3:20 pm
GilaMonster (6/5/2009)
Lynn Pettis (6/5/2009)
GilaMonster (6/5/2009)
Lynn Pettis (6/5/2009)
Here is another OMG moment.
He may have just misunderstood what BoL was. I'd be a little unhappy if I asked a simple question and...
June 5, 2009 at 3:12 pm
GilaMonster (6/5/2009)
Lynn Pettis (6/5/2009)
Here is another OMG moment.
He may have just misunderstood what BoL was. I'd be a little unhappy if I asked a simple question and was told to...
June 5, 2009 at 3:04 pm
I'd also like to suggest this blog entry as well, The Flip Side. It may also provide you with additional insight in how to deal with those of us...
June 5, 2009 at 2:43 pm
I'm not telling you to buy ANY books. Books Online is the SQL Server Help file. While in SSMS, press F1, it will bring it up.
June 5, 2009 at 2:36 pm
My I suggest that you rerun that last query and put the data into an Excel spreadsheet and attach that? I can't tell which values belong to header, and...
June 5, 2009 at 2:31 pm
Look up maintenance plans in BOL. That is a good place to start.
June 5, 2009 at 1:48 pm
rsaylors (6/5/2009)
June 5, 2009 at 1:34 pm
GSquared (6/5/2009)
declare @Test datetime;--
select @Test = '6/5/09 1:12 pm';
--
select dateadd(hour, datediff(hour, 0, @Test), 0);
You can use that dateadd(datediff()) method for taking any part of a datetime off. Works very...
June 5, 2009 at 12:02 pm
This one is simple:
declare @ThisDate datetime;
set @ThisDate = getdate();
select @ThisDate, dateadd(hh, datediff(hh, 0, @ThisDate), 0)
June 5, 2009 at 11:12 am
Viewing 15 posts - 20,566 through 20,580 (of 26,484 total)