Viewing 15 posts - 11,581 through 11,595 (of 13,469 total)
there is a built in procedure to get all your objects in dependancy order:
EXEC sp_msdependencies @intrans = 1
I've only used it to build script, and not to drop...
February 15, 2009 at 1:03 pm
I think you are planning the right way. I try to analyze the issue like this:
say i was going to support Spanish language version of my data, and consider...
February 15, 2009 at 8:26 am
you really need to start with creating a trace with profiler....create one and let it run for a while...I'd say one business day.
with that, it will give you every query,...
February 15, 2009 at 8:17 am
somewhere in your classes, notes and lectures, you must have heard there is an INFORMATION about SCHEMA information in the database I wonder if you were to look at some...
February 15, 2009 at 8:08 am
With this being your final year project at school, it wouldn't be right for us to do the work...you'd never gain the knowledge by copying our code. Being aware of...
February 15, 2009 at 7:29 am
you were so close on the syntax;
to assign to a static value, you usually use SET; but
you can assign a variable inside a select, like SELECT @CITY=CITY,@STATE=STE FROM ADDRESSES....
here's...
February 13, 2009 at 6:34 pm
dunno why i keep looking at this...
you can add a trigger on the VIEW to handle the status column....
rename the original table.
--add a view that has the old table name...
February 13, 2009 at 5:47 pm
Lynn he had stated previously that he actually has to check a couple other tables to get the true status...i think this was just a simplified example....since he's got to...
February 13, 2009 at 4:10 pm
the point trying to make, is that if the "status" is based on criteria, which you said was a combination of the end date and other factors in other tables,...
February 13, 2009 at 3:51 pm
Here's a complete example for you...
you simply change whatever application is looking at "my_table" to report the current status to point to "ViewOfMyTable"...all done...no process needing to run every thirty...
February 13, 2009 at 3:09 pm
well...you can have a calculated column as a primary key...so i'd make it built off of an identity like this:
[font="Courier New"]CREATE TABLE #example(myid INT IDENTITY(1,1),
myCalculatedPK AS 'martmp_' + RIGHT('00000000' +...
February 13, 2009 at 12:32 pm
select
ALIAS1.naam,
ALIAS1.Aantal_Incidenten,
ALIAS2.naam,
ALIAS2.Aantal_Inc_Portal
FROM
(
select vestiging.naam, count(*) as Aantal_Incidenten
from incident, vestiging
where incident.aanmeldervestigingid = vestiging.unid
group by vestiging.naam
) ALIAS1,
(
select vestiging.naam, count(*) as Aantal_Inc_Portal
from incident,...
February 12, 2009 at 10:57 am
another way to do it wiht a CASE statement, if you need to do lots of different race codes:
SELECT
SUM(CASE WHEN race_code = '01' THEN 1 ELSE 0...
February 12, 2009 at 10:39 am
it's suprisinglyy easy... you just need to use the two tables as aliased subselects:
SELECT ALIAS1.AM,ALIAS2.CM
FROM
(SELECT COUNT(*) AS AM
FROM dwh_test.dim_employees
WHERE
...
February 12, 2009 at 10:28 am
the trick for # of recurring substrings in a string is to use the replace function:
declare @MySchedule varchar(168)
SET @MySchedule = REPLICATE('123456789',40) --overkill
select @MySchedule
/*results:
123456789123456789123456789123456789123456789
123456789123456789123456789123456789123456789
123456789123456789123456789123456789123456789
123456789123456789123456789123456
*/
--how many times is there a 9 in...
February 12, 2009 at 9:47 am
Viewing 15 posts - 11,581 through 11,595 (of 13,469 total)