Viewing 15 posts - 1,801 through 1,815 (of 2,171 total)
The power function is only calculated for the five fields!
POWER(0, 2) + POWER(7, 2) + POWER(7, 2) + POWER(0, 2) + POWER(0, 2) is 98
POWER(9, 2) + POWER(0, 2) +...
October 17, 2006 at 6:18 am
And welcome to SQLTeam, you are much needed there.
October 17, 2006 at 5:52 am
I did not call you insane. Believe me. You are one of the clever people here.
I call oracle_corrgi insane. It is not good to put same question on several forums,...
October 17, 2006 at 5:50 am
October 17, 2006 at 4:13 am
Cross posting http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=73268
October 10, 2006 at 3:02 am
September 5, 2006 at 1:25 am
Collation is the set of characters used to represent your or any other's alphabet.
We in Sweden most often use the FINNISH_SWEDISH collation to be able to view...
September 5, 2006 at 1:24 am
You can also use the Levesthein Edit Distance algorithm found here
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=51540
September 1, 2006 at 7:14 am
Cross posting. Topic already answered here
http://www.sqlservercentral.com/forums/shwmessage.aspx?forumid=145&messageid=305549
September 1, 2006 at 6:34 am
I think this is a better approach for this task. But you are right otherwise Andrew!
DECLARE @search VARCHAR(10),
@MaxDigitsWrong TINYINT
SELECT @Search = '1644705509',
@MaxDigitsWrong = 2
DECLARE @Test TABLE (PartNo...
September 1, 2006 at 6:31 am
It is not pretty, but it works.
declare @test table (NoOfItems varchar(100), Quantities varchar(100))
insert @test
select '1,2,10,15,1,1',
'50,75,20,100,20,25'
DECLARE @Items TABLE (i INT IDENTITY(0,1), Value INT)
INSERT @Items
(
Value
 ![]()
August 31, 2006 at 1:09 am
I don't think there is a way to accomplish this?
How will SQL Server distinguish between "Sue" and "JDAL"?
August 28, 2006 at 11:30 am
Viewing 15 posts - 1,801 through 1,815 (of 2,171 total)