Viewing 15 posts - 421 through 435 (of 683 total)
Wow! What a comprehensive reply. Nice work, Jeff ![]()
You must either have far too much time on you hands or you are a really,...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 31, 2006 at 9:53 am
I didn't know that (about the v9 update) - thanks Tim. The boys at MS have been working hard... ![]()
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 31, 2006 at 7:29 am
Note that you should run "DBCC UPDATEUSAGE (MyDatabase)" first for Tim's query to be accurate. That is the best method though.
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 31, 2006 at 5:19 am
Here's some more ideas for splitting... http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=50648 (including the one from Peter above)
Peter - I think I've successfully deduced that you are Peso on SQLTeam ![]()
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 31, 2006 at 4:44 am
Well, I was enjoying the kind feedback, and then I came across your idea, Peter. Very nice indeed! ![]()
I think I've been outdone...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 30, 2006 at 5:45 am
Nagabhushanam Ponnapalli - try adding '1.10' to your data ![]()
Here's a (relatively) simple idea/solution with the limitation...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 26, 2006 at 12:28 pm
Hi all,
Chris - not wanting to be critical
, but more elegantly that what? Those 2 techniques are both listed, along with others, in this link...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 25, 2006 at 3:59 am
Hi Afendi,
Sounds like you're going to need a tally/numbers table. Here's an illustration of the technique... ![]()
You may need to use a trigger to...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 9:47 am
Good stuff ![]()
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 5:47 am
Post your table structure, some sample data and the result you want for that sample data. Here's an example (for a different question)...
--I...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 5:44 am
Hi all,
Tony - it sounds like you only want the ones that have a count of more than one, so maybe you need something like this...
select dbo.uf_stripnonalpha(colname)...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 5:35 am
Hi all,
Tryst - You might want to consider storing the lineage (breadcrumb) in a column in your table. These articles endorse that and show you how to do it (again...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 5:27 am
Whenever you think about a cursor, slap yourself and tell yourself there must be a better way. ![]()
Post your table structure, some sample data...
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 5:05 am
Also see...
http://vyaskn.tripod.com/passing_arrays_to_stored_procedures.htm
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=50648
http://www.sommarskog.se/arrays-in-sql.html
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 5:02 am
There are a few methods to do what you need, and this article discusses them and their pros and cons...
http://www.sql-server-performance.com/mm_list_random_values.asp
Ryan Randall
Solutions are easy. Understanding the problem, now, that's the hard part.
May 24, 2006 at 4:47 am
Viewing 15 posts - 421 through 435 (of 683 total)