Viewing 15 posts - 526 through 540 (of 583 total)
I have not yet changed the -g switch setting because I wanted to be sure that it would help before doing so. The setting was in place when I started...
January 22, 2009 at 9:43 am
I agree with John, the better the example, the better the help.
From the sounds of it you are on the right track. Using Outer join instead of inner join...
January 16, 2009 at 11:09 am
How is the security on the linked server setup?
January 15, 2009 at 2:07 pm
Since you are new to SQL this is a good learning opportunity. What I think you want to do is to have BO, CT and Total in the same...
January 15, 2009 at 1:41 pm
I would say all you need to do is joins the results of the 3 views on the cleareddate column.
January 15, 2009 at 12:48 pm
bocleared cleareddate ctcleared cleareddate totalcleared cleareddate
2 1/2/2009 ...
January 15, 2009 at 11:03 am
Are you seeing any errors in the Application or system event logs at the same time as the errors in sql server log? I am seeing the same errors in...
January 15, 2009 at 10:49 am
This probably will not return the correct results based on original query you posted. You will get something that looks right but the data may be wrong.
Again look online for...
January 13, 2009 at 8:06 am
What I posted is an example. It has nothing to do with your actual query except demonstrating what changes you would need to make in your own. Since you don't...
January 13, 2009 at 7:57 am
A quick example on how you can get you results. Just take the example and apply it to your query.
This code creates the test data
create table ocode(
officecodevarchar(2),
datedatetime,
numint)
insert into ocode
select 'bo',getdate(),1
union...
January 12, 2009 at 3:36 pm
After re-reading the question, there may be an easier way to get what you need without a pivot table. in your CTE, include Office Code as one of the columns...
January 12, 2009 at 2:14 pm
I think the using PIVOT command may be able to get you your results.
January 9, 2009 at 2:41 pm
The following will give you similar info, product level states SP.
select serverproperty('ProductVersion') as ProductVersion,serverproperty('Edition') as Edition,serverproperty('ProductLevel') as ProductLevel
and this link has list of build version
http://www.sqlservercentral.com/articles/Administration/2960/%5B/url%5D
January 9, 2009 at 2:12 pm
the registry path this would be located in is
HKEY_CLASSES_ROOT\Installer\patches
January 6, 2009 at 3:30 pm
As for whether you should install the SP2 or RTM support files or do it at all since it installed correctly i cant say because me situation was not exactly...
January 6, 2009 at 3:27 pm
Viewing 15 posts - 526 through 540 (of 583 total)