Viewing 15 posts - 5,911 through 5,925 (of 7,636 total)
Excellent observation, Jonathan. thanks for passing it along. 🙂
August 14, 2008 at 12:23 pm
andrew gothard (8/12/2008)
August 14, 2008 at 11:48 am
You created it in the wrong Master schema. It has to be in the SYS schema.
August 14, 2008 at 11:22 am
Tom Brown (8/14/2008)
Then I'd need a CDTagUsers table or a DentistTagUsers table, so can you see any merit in having a generic UserTags Table
Functionally, its only benefit is if you...
August 14, 2008 at 11:15 am
K. Brian Kelley (8/14/2008)
August 14, 2008 at 11:03 am
I'm still trying to figure out the point of IM'ing! :w00t:
It makes about as much sense to me as getting a DSL/Cable/Fiber service and then trying to run my...
August 14, 2008 at 10:56 am
JBANKO (8/14/2008)
August 14, 2008 at 10:45 am
The obvious supporting views:
--====== add some views
Create View vwBookTags as
Select BookID
, TagID
, Min(Tags.Label)
, Count(UserID) as TagCount
From BookTagUsers
Join Tags ON BookTagUsers.TagID = Tags.TagID
Group...
August 14, 2008 at 10:25 am
Well, this is how I would start; The straight-forward relational way:
/*
User table, Author and Book tables and an AuthorBookLink table.
Instead of giving each book a single category,...
August 14, 2008 at 10:18 am
Chandru (8/14/2008)
one more thing the random generated number it should notrepeate again
As Gus alluded to, this constraint...
August 14, 2008 at 9:14 am
I agree with Lowell, I know lots of ways to write a pseudo-random number generator but I am not going to bother until I understand what the real constraints are...
August 14, 2008 at 9:07 am
This should work:
Select * From (
Select A.Material, A.Maint_status,
CASE When CharIndex(Substring(A.Maint_status,1,1), B.Maint_status) > 0
Then ''
Else Substring(A.Maint_status,1,1) End
+CASE When CharIndex(Substring(A.Maint_status,2,1), B.Maint_status) > 0
Then ''
Else Substring(A.Maint_status,2,1) End
+CASE When CharIndex(Substring(A.Maint_status,3,1), B.Maint_status) > 0
Then ''
Else...
August 14, 2008 at 8:54 am
Questions:
1. Can the characters (K, C, V, D, B) be in any order in both tables?
2. should we worry about records in Table A that have no matching Material value...
August 14, 2008 at 8:33 am
I would suggest checking your master procedure.
August 14, 2008 at 8:27 am
Viewing 15 posts - 5,911 through 5,925 (of 7,636 total)