Viewing 15 posts - 2,356 through 2,370 (of 5,504 total)
What's the data type of StartTime?
December 22, 2010 at 4:22 pm
Gagne (12/22/2010)
Lutz, that sounds like you're saying that generally speaking, virtualizing a SQL Server will impact performance and that it's all a question of whether it will slow it down...
December 22, 2010 at 4:20 pm
Here's my approach:
; WITH cte AS
(
SELECT dt,id,MAX(statusdate) AS max_statusdate
FROM ReportDate rd
LEFT OUTER JOIN CustomerInfo ci ON ci.statusdate<=rd.dt
GROUP BY dt,id
)
SELECT
dt AS [Report DATE] ,
SUM(CASE...
December 22, 2010 at 4:01 pm
I, personally, find Brent Ozar's blog[/url] very informative ,especially including the comments and the follow-up article. Those two articles combined give a neutral (if possible at all) point of view...
December 22, 2010 at 3:25 pm
Paul,
it seems like you're not really interested in helping us help you.
Instead of providing the information we asked for multiple times you decide to open new threads with the...
December 22, 2010 at 2:54 pm
Instead of using SELECT * you'd need to specify each column and use alias column names for the duplicates (like a.ACCOUNT, b.ACCOUNT, a.COD, c.CODE and maybe some more columns).
The reason...
December 22, 2010 at 2:33 pm
JStevenson1 (12/22/2010)
I have several value in a column called test.Select Statement: Select Test From Abc
Output: JonDoe
Desired Output: 'JonDoe'
How do I achieve desired output?
Something like the following code? (assuming all...
December 22, 2010 at 2:23 pm
Here's a version that will provide the structure as requested based on Waynes sample data and sample code (Thank you, Wayne!!).
However, due to the DTD declaration you won't be able...
December 22, 2010 at 2:06 pm
May the Holidays be silent and without any release changes you need to take care of!
My plan for the Holidays (with my kids):
We have slightly more snow than...
December 22, 2010 at 1:14 pm
I'll have a look at it within the next hour. Promise.
December 22, 2010 at 12:42 pm
pwalter83 (12/22/2010)
I have attached all the relevant documents which are being used for this query. Would that be enough ?
Here's a short SQL puzzle for you:
SELECT @answer = result FROM...
December 22, 2010 at 12:40 pm
pwalter83 (12/22/2010)
Hi LutzM,What exactly do you need from my side to resolve this issue ?
...
Please read and follow the instructions given in the first article referenced in my signature,...
December 22, 2010 at 9:59 am
sotn (12/22/2010)
thanks for the reply.
I am a little confused as my previous post shows that my tables have completely different field names and number of fields so I cannot...
December 22, 2010 at 7:14 am
sotn (12/22/2010)
Any ideas how to produce this format?
Yes (concept as mentioned before).
For a coded version please provide ready to use sample data as described in the first link in my...
December 22, 2010 at 6:33 am
Viewing 15 posts - 2,356 through 2,370 (of 5,504 total)