Viewing 15 posts - 706 through 720 (of 854 total)
Thank you very much, it worked, so just to understand how instr translates in sql?
Example:InStr(1,[last_name]," ")
March 17, 2009 at 8:47 am
I am sorry, but this code is incorect is not giving me a right data:
This is what I need:
I have data:
First Name ...
March 16, 2009 at 10:43 am
Thank you, what about my second :
I need to convert this:
Right([Field3],(Len([Field3])-InStr(1,[Field3]," "))) & [Field4]
Joe's code:
RIGHT(FIELD3,LEN(LEFT([FIELD3],PATHINDEX(' ',[FIELD3])-1))+[FIELD4]
I did this: --(Field3 =FirstName and Field4 Last Name)
RIGHT (FIRST_NAME, LEN(LEFT (FIRST_NAME, PATINDEX(' ', FIRST_NAME)...
March 16, 2009 at 9:17 am
Thank you
March 9, 2009 at 11:51 am
Can you showe me how to do it please. Thank you
March 9, 2009 at 9:59 am
I am confused, sorry, how can I put it together in the query of the SQL Server. Thank you
March 9, 2009 at 7:01 am
Also, how can I convert this:Len(Left([Field3],InStr(1,[Field3]," or")-1)) Thank you
March 6, 2009 at 12:46 pm
Thank you, so
NA: Right([Field6],Len([Field6])-InStr(1,[Field6],"Unit")+1)
is equeal to this
RIGHT([Field6], LEN([Field6]) - CHARINDEX('Unit', [Field6]) + 1)
or this
SUBSTRING([Field6], CHARINDEX('Unit', [Field6]), 100)
right?
Your recomendation to use this:SUBSTRING([Field6], CHARINDEX('Unit', [Field6]), 100) ...
March 6, 2009 at 12:17 pm
Viewing 15 posts - 706 through 720 (of 854 total)