Viewing 15 posts - 3,316 through 3,330 (of 7,187 total)
I would suggest a slight modification to the above, since the previous ID is not always going to be the current ID minus 1 (there will be gaps). Also,...
November 27, 2014 at 4:35 am
Dave
The problem with a maintenance plan is you don't have much control over what it does. What you want to do is only rebuild the indexes that need it....
November 25, 2014 at 9:54 am
Jeff
It's easy enough to install. You don't even have to run it on the same server as you're doing the ETL on. If it's really not an option,...
November 25, 2014 at 8:19 am
Jeff
I would use SSIS (or your favourite other way of doing ETL) to bring the data from the remote servers into Access. Don't use linked servers at all -...
November 25, 2014 at 8:13 am
Have a look at the properties of the linked server, and go the the Security tab. Are there any logins listed in the box at the top? Which...
October 24, 2014 at 2:23 am
No, SQL Server waits ad infinitum for locks to be released. As Gianluca suggested, please use sp_who2 or sp_whoisactive to find out whether there is any blocking. What...
October 23, 2014 at 9:46 am
You're looking for a splitter function. Try this search for a start.
John
Edit: oops - I just realised that you were asking for an expression in SSIS to do...
October 23, 2014 at 8:20 am
I think Ola Hallengren's procedures will automatically take a full backup if one doesn't exist.
John
October 23, 2014 at 5:58 am
You can do it by breaking each permission down into a sum of powers of two. Something like this should work:
SELECT UserName, ServerOperation, SUM(DISTINCT p)
FROM #Operations o
OUTER APPLY (
SELECT...
October 22, 2014 at 3:36 am
I see - you want to find out which groups a particular user is a member of, rather than which users are members of a particular group? That's a...
October 22, 2014 at 2:14 am
Or more generally, using an outer join:
CREATE TABLE MyProducts (ProdID int, ProdGrp char(7))
INSERT INTO MyProducts VALUES
(11, '*')
,(12, '*')
,(13, 'Group A')
,(14, 'Group B')
,(15, 'Group C')
CREATE TABLE MyGroups (ProdGrp char(6), ProdGrpDesc...
October 21, 2014 at 9:55 am
Try passing in your date in an unambiguous form, such as '20141001'.
John
October 21, 2014 at 9:28 am
Time for you to use your favourite search engine to investigate, then. It's a fully documented stored procedure.
John
October 21, 2014 at 6:57 am
EXEC xp_logininfo 'DomainName\GroupName', 'members'
John
October 21, 2014 at 2:05 am
Viewing 15 posts - 3,316 through 3,330 (of 7,187 total)