Return Previous business day

  • Hello All

    I am looking to return the previous business day from a function.

    USE [MYDB]
    GO

    SET ANSI_NULLS ON
    GO

    SET QUOTED_IDENTIFIER ON
    GO

    CREATE FUNCTION [dbo].[F_PreviousBusinessDay]
    (
    @DateInput DATE
    )
    RETURNS DATE
    AS
    BEGIN
    DECLARE @DateOutput DATE = @DateInput
    DECLARE @returnDate DATE
    --Weekend
    BEGIN
    SET @DateOutput = DATEADD(DAY,
    CASE when datepart (dw,@DateInput) < 3 then datepart (dw,@DateInput) * -1 + -1 ELSE -1 END,
    cast(@DateInput as date))
    END
    --Holidays
    IF EXISTS(SELECT HolidayDate from dbo.AAA_Tbl_Admin_Holidays WHERE HolidayDate = @DateInput)
    BEGIN
    SET @DateOutput = DATEADD(DAY,-1,@DateInput);
    SET @DateOutput = (SELECT dbo.F_PreviousBusinessDay(@DateOutput))
    END

    RETURN @DateOutput;
    END

    GO

    The above code is called:

    select DBO.F_PreviousBusinessDay('2019-06-02') Return_Date

    Or

    Declare @attendancedate date;
    set @attendancedate = getdate()
    select dbo.F_PreviousBusinessDay(@attendancedate)

    If I run this, the function seems to return the date I passed to the function. This is not right.  The above code should return 04-06-2019.  However, if I pass 2019-06-02 to the function it returns 2019-05-31.  This would indicate that Saturday is being recognised as a day to omit, but not Sunday and it seems not to find the holiday also.  for testing I create 2019-06-03 as a test holiday.

    So far I think I've worked out that the date is not being read correctly, i.e. 2019-06-03 00:00:00.000, should be 2019-06-03, but I don't know how to resolve.

    Can anybody help correct my code.  Otherwise, I am looking to return the previous business day, omitting saturday, Sunday, and public Holidays as recorded by my holiday table.

    Thanks

     

     

    • This topic was modified 4 years, 10 months ago by  barry.nielson.
    • This topic was modified 4 years, 10 months ago by  barry.nielson.
  • Your function is a scalar function, which has terrible performance.

    Below is an iTvf (inline table valued function) that will get the last business day

    CREATE FUNCTION [dbo].[F_PreviousBusinessDay]
    (
    @DateInput DATE
    )
    /* Usage:

    -- Single Value
    SELECT PreviousBusinessDay
    FROM [dbo].[F_PreviousBusinessDay](GETDATE());

    --Table of Values
    SELECT PreviousBusinessDay
    FROM YourTable
    CROSS APPLY [dbo].[F_PreviousBusinessDay](YourTable.DateField);
    */
    RETURNS TABLE
    AS RETURN

    -- First get the last (14) dates. This assumes that there will be a working day in there.
    -- By changing the value in TOP(14), you can get up to 100 days back.
    WITH T(N) AS (SELECT N FROM (VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) AS X(N))
    , DATES(D) AS (SELECT TOP(14) DATEADD(dd, -ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), @DateInput)
    FROM T T1 CROSS JOIN T T2)
    SELECT PreviousBusinessDay = MAX(d.D)
    FROM DATES as d
    WHERE DATEDIFF(dd, 0, d.D) %7 <= 4 -- Exclude weekends ... 0=Monday, 6=Sunday
    AND NOT EXISTS (SELECT 1 FROM dbo.AAA_Tbl_Admin_Holidays AS h
    WHERE h.HolidayDate = d.D)
    GO

     

  • Thanks for your help and effort to code this.

    I've run this and it seems to work beautifully.  There's no chance I would have figure out this so thanks a lot.

     

     

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