CTE - a simpler solution?

  • All,

    I'm trying to get the average number of relatedpostid counts per postid. The following achieves the result I want:

    create table postlinks (postid int ,relatedpostid int)

    insert into postlinks(postid,relatedpostid) values (5,1)
    insert into postlinks(postid,relatedpostid) values (5,2)
    insert into postlinks(postid,relatedpostid) values(6,1)
    insert into postlinks(postid,relatedpostid) values(6,2)
    insert into postlinks(postid,relatedpostid) values(6,3)
    insert into postlinks(postid,relatedpostid) values(6,4)


    with postcount (postid,postcount) as
    (
    select postid,count(relatedpostid) as postcount from postlinks
    group by postid)

    select avg(postcount) from postcount

    However I'm wondering if there is a simpler way of getting the average that I've missed?

  • Looks ok to me.

    If you want non-integer averages you can do this by adding 0.0 to the count:

    with postcount (postid,postcount) as 
    (
    select postid,count(relatedpostid)+0.0 as postcount
    from postlinks
    group by postid
    )
    select avg(postcount)
    from postcount
  • Does this work?

    SELECT COUNT(*) / COUNT(DISTINCT p.postid)
    FROM postlinks p;

    If you haven't even tried to resolve your issue, please don't expect the hard-working volunteers here to waste their time providing links to answers which you could easily have found yourself.

  • Both,

    Thank you for your help.

    Jonathan: Thanks, I hadn't realised it had rounded to an int. Am I correct in thinking that AVG will return an int if it receives an int and a decimal if it receives a decimal? Having seen your post I seem to remember that it works like that but I couldn't find a reference online to check.

    Phil: Thanks. I think it is the same, although my maths is not brilliant! It also returns an int rather than a decimal. I'm currently working on trying to make it a decimal, if I work it out I'll post incase it helps others.

  • Returning a decimal is easy:

    SELECT CAST(COUNT(*) AS DECIMAL(19,6)) / COUNT(DISTINCT p.postid)

    If you haven't even tried to resolve your issue, please don't expect the hard-working volunteers here to waste their time providing links to answers which you could easily have found yourself.

  • It is returning an integer because count returns an integer value.  By adding the 0.0 to it, it does an implicit conversion to decimal.

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    http://www.sqlservercentral.com/articles/Best+Practices/61537/

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    http://www.sqlservercentral.com/articles/SQLServerCentral/66909/

  • All,

    Thanks for your help.

     

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