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Script Component


Script Component

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lzlzgh
lzlzgh
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Group: General Forum Members
Points: 15 Visits: 145
I am trying to get the file name with a for each loop container and a script component but I receive an error on the script component: Below is the script:

Public Sub Main()
Dim FileName As String
Dts.Variables("User::FileName").Value = System.IO.Path.GetFileName(Dts.Variables("User::FileName").Value.ToString())
Dts.TaskResult = Dts.Results.Success

End Sub
Koen Verbeeck
Koen Verbeeck
SSC Guru
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Group: General Forum Members
Points: 99732 Visits: 13322
What is the error that you get?

And why do you create a variable Filename that you don't use?

The following solution should work:

map the SSIS variable FileName in the For Each Loop to index 0 (see variable mappings).
Then, in your script component, use this code (make sure you add the variable FileName is a read-only variable in your script component/task):

Public Sub Main()
Dim FileName As String
FileName = Dts.Variables("User::FileName").Value.ToString()
Msgbox(Filename) 'To test it
Dts.TaskResult = Dts.Results.Success

End Sub




Note: if you use a script component, you should use Me.Variables.FileName to access the variable.


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Stewart "Arturius" Campbell
Stewart "Arturius" Campbell
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Group: General Forum Members
Points: 24813 Visits: 7502
From what you have stated, I presume you are running through a folder with numerous (1 or more) files to be imported.
when you create a foreach loop to iterate through a folder, you will have created a variable to hold the file name (eg @User::FileName).

thus, for each iteration, the variable is populated with the relevant file name being retrieved.
this variable can then be used in any subsequent process (constraint in the process flow, in a conditional split, added to the list of columns using a derived column component and captured in a table, etc.

the question to be answered therefore: what is it you need to achieve with the file name?

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Attachments
ForEachLoopExample.zip (22 views, 59.00 KB)
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