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SQL Query to find out MAX Qty and MAX Childitem of a parent item


SQL Query to find out MAX Qty and MAX Childitem of a parent item

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yvbchowdary
yvbchowdary
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Hi Folks,

I need to write a query to find out all the parent items which has a MAX of Qty and Max of Childitem. Here the process is like, first we need to get the MAX Qty per Parent and for this Qty get the MAX of Childitem.

Parent Item ChildItem Qty
62338-87468-00 62338-77961-20 45.333
62338-87468-00 62338-77961-18 45.333
62338-87468-00 62338-84683-21 45.333
62338-87468-00 62338-84683-18 46
62338-87468-00 62338-87135-01 46
62338-87468-00 62338-87135-00 45

From the above example, there are two childitems of the MAX Qty. so the final output should be 62338-87468-00(parent), 62338-87135-01(Child), 46(Qty). It means there should be only one row per each parent item.

Help would be greatly appreciated.

Thank you,
Venu Babu,
mister.magoo
mister.magoo
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Group: General Forum Members
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It helps if you provide your data in a re-usable format , such as this:


with data(ParentItem,ChildItem,Qty)
as
(
select '2338-87468-00', '62338-77961-20', '45.333' union all
select '2338-87468-00', '62338-77961-18', '45.333' union all
select '2338-87468-00', '62338-84683-21', '45.333' union all
select '2338-87468-00', '62338-84683-18', '46' union all
select '2338-87468-00', '62338-87135-01', '46' union all
select '2338-87468-00', '62338-87135-00', '45'
),

-- Here is the query you need

RowNumbered(ParentItem,ChildItem,Qty,Rn) as
(
select *,row_number() over(partition by ParentItem order by Qty desc,ChildItem desc) as Rn
from data
)
select ParentItem,ChildItem,Qty
from RowNumbered
where Rn=1



I have done it for you because you are new here :-)

MM


select geometry::STGeomFromWKB(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  • yvbchowdary
    yvbchowdary
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    Group: General Forum Members
    Points: 7 Visits: 131
    Thanks Buddy this helped me a lot to complete my Proc.
    petereg33
    petereg33
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    Group: General Forum Members
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    thanks for the info :-)
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