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Replacing a string when the value is found in a table


Replacing a string when the value is found in a table

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Jani Lane
Jani Lane
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Hi guys,

I'm trying to create a function where I can pass a string value that will be used for searching a table column and see if there is match, then replace that string partially when found like below:

Passed string: "John Doe University"

The column values from the table:

SELECT LastName FROM ThisTable
--------------------------------

LastName
---------
Cruz
Patar
Doe
QuiJong
Halal

So if the search is succesful, I'll replace the string with empty string, then the value will be returned as:

John University


Hope it makes sense?

Thanks
Sergiy
Sergiy
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select @SearchString = REPLACE(@SearchString, LastName, '')
FROM ThisTable
select @SearchString
Steven Willis
Steven Willis
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Not exactly clear on what you are trying to accomplish, but my first instinct is to suggest the STUFF function. You can google it.

 
Jani Lane
Jani Lane
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Thanks guys, Sergiy's answer is exactly what I needed.

Have a nice day.:-)
kapil_kk
kapil_kk
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Sergiy (5/2/2013)
select @SearchString = REPLACE(@SearchString, LastName, '')
FROM ThisTable
select @SearchString

+1 :-)

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