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The argument 1 of XML datatype method nodes must be string literal.plz help


The argument 1 of XML datatype method nodes must be string literal.plz help

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suvo.kundu
suvo.kundu
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declare @starttag varchar(100)
declare @root varchar(100)
set @starttag ='XML'
set @root ='XML'

Declare @xml xml
Set @xml =
'<XML>
<Provider>
<providerID>1</providerID>

<Address>address1</Address>

</Provider>

<Provider>
<providerID>2</providerID>

<Address>address2</Address>

</Provider>
<Provider>
<providerID>3</providerID>

<Address>address3</Address>
<city>kol</city>

</Provider>

</XML>'


SELECT
dense_rank() OVER (ORDER BY C.value('local-name(.)', 'varchar(50)')) AS 'SN',
NodeName = C.value('local-name(.)', 'varchar(50)')
, NodeValue = C.value('(.)[1]', 'varchar(50)')
FROM @xml.nodes('/XML/Provider/*') AS T(C)

But if the sql is

SELECT
dense_rank() OVER (ORDER BY C.value('local-name(.)', 'varchar(50)')) AS 'SN',
NodeName = C.value('local-name(.)', 'varchar(50)')
, NodeValue = C.value('(.)[1]', 'varchar(50)')
FROM @xml.nodes('/'+@starttag +'/'+@root+'/*') AS T(C)

it gives error as

The argument 1 of XML datatype method nodes must be string literal..plz help
Arthur Olcot
Arthur Olcot
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The argument 1 of XML datatype method nodes must be string literal..plz help


This means that the argument that you are specifying within the nodes() function must be a string literal like you have done in the first SELECT and not a constructed string as you are trying to use in the second SELECT. You cannot use a variable either.
Mark Cowne
Mark Cowne
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Use sql:variable


set @starttag ='XML'
set @root ='Provider'

SELECT
dense_rank() OVER (ORDER BY C.value('local-name(.)', 'varchar(50)')) AS 'SN',
NodeName = C.value('local-name(.)', 'varchar(50)')
, NodeValue = C.value('(.)[1]', 'varchar(50)')
FROM @xml.nodes('/*[local-name(.)=sql:variable("@starttag")]/*[local-name(.)=sql:variable("@root")]/*') AS T(C)



____________________________________________________

Deja View - The strange feeling that somewhere, sometime you've optimised this query before

How to get the best help on a forum

http://www.sqlservercentral.com/articles/Best+Practices/61537




Arthur Olcot
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Nice.... I like that solution Smile
suvo.kundu
suvo.kundu
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actually the out put of the query changes using ur suggestion.The value of SN column changes
set @starttag ='XML'
set @root ='Provider'

SELECT
dense_rank() OVER (ORDER BY C.value('local-name(.)', 'varchar(50)')) AS 'SN',
NodeName = C.value('local-name(.)', 'varchar(50)')
, NodeValue = C.value('(.)[1]', 'varchar(50)')
FROM @xml.nodes('/*[local-name(.)=sql:variable("@starttag")]/*[local-name(.)=sql:variable
OUTPUt:-
SN NodeName NodeValue
1 Address Address3
3 providerID 2
3 providerID 1
1 Address Address2
1 Address Address1
3 providerID 3
2 City Kol






My desired out put is
SN NodeName NodeValue
1 Address address1
1 Address address2
1 Address address3
2 city kol
3 providerID 1
3 providerID 3
3 providerID 2
Mark Cowne
Mark Cowne
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Try adding

ORDER BY SN,NodeName,NodeValue



to the end of the query

____________________________________________________

Deja View - The strange feeling that somewhere, sometime you've optimised this query before

How to get the best help on a forum

http://www.sqlservercentral.com/articles/Best+Practices/61537




suvo.kundu
suvo.kundu
Grasshopper
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Group: General Forum Members
Points: 17 Visits: 80
SELECT
dense_rank() OVER (ORDER BY C.value('local-name(.)', 'varchar(50)')) AS 'SN',
NodeName = C.value('local-name(.)', 'varchar(50)')
, NodeValue = C.value('(.)[1]', 'varchar(50)')
FROM @xml.nodes('/XML/Provider/*') AS T(C)

actually the xml that i am fetching is very large approx 5mb in size with lots of child nodes.
it is taking a lot of time..plz suggest alternative option with this query.
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