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Problem using expression in SSIS


Problem using expression in SSIS

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Devesh_Srivastava
Devesh_Srivastava
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Hi,

Below is the expression i am trying to make work :

substring ("Archive_Full_20120731200002",1, (FINDSTRING( "Archive_Full_20120731200002","Full_", 1)-2))


Whe I use the exact string(Archive_Full_20120731200002) , I get the required result i.e Archive
But when I use a variable which contains th same string, the above expression gives the error that
Substring can allow -ve integer values( Here -2)

Please help me in this regard. I need to use a variable here and get it work.

Your help is appreciated!!!

Thanks
Devesh
Phil Parkin
Phil Parkin
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Please post the expression which you tried - the one which gives the error.


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Devesh_Srivastava
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Below is the expression to be evaluated:

Substring (@Variable,1, (FINDSTRING( @Variable,"Full_", 1)-2))

@Variable is the variable containing the exact string 'Archive_Full_20120731200003'

But when i used this as a expression, it gives the error that substring does not allow -ve integer values.

Kindly help.
herladygeekedness
herladygeekedness
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Substring cannot take negative values for the length argument.
Devesh_Srivastava
Devesh_Srivastava
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substring ("Archive_Full_20120731200002",1, (FINDSTRING( "Archive_Full_20120731200002","Full_", 1)-2))

Then how come the above expression is working where the exact string is used instead of a variable and still negative value is accepted!!! Does it make sense ?
Phil Parkin
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Works for me. I suspect that you may have got your variable syntax wrong. Here is my version:

Substring (@[User::TestString],1, (FINDSTRING(@[User::TestString] ,"Full_", 1)-2))




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herladygeekedness
herladygeekedness
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Devesh_Srivastava (8/1/2012)
substring ("Archive_Full_20120731200002",1, (FINDSTRING( "Archive_Full_20120731200002","Full_", 1)-2))

Then how come the above expression is working where the exact string is used instead of a variable and still negative value is accepted!!! Does it make sense ?


Good question. I only know that when attempting to put in a negative value for length in a much simpler expression, it errored on negative value of length parameter.
Phil Parkin
Phil Parkin
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herladygeekedness (8/2/2012)
Devesh_Srivastava (8/1/2012)
substring ("Archive_Full_20120731200002",1, (FINDSTRING( "Archive_Full_20120731200002","Full_", 1)-2))

Then how come the above expression is working where the exact string is used instead of a variable and still negative value is accepted!!! Does it make sense ?


Good question. I only know that when attempting to put in a negative value for length in a much simpler expression, it errored on negative value of length parameter.



The result of

FINDSTRING( "Archive_Full_20120731200002","Full_", 1) -2



is 7. That's not a negative value where I come from :-)


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herladygeekedness
herladygeekedness
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Not talking about the result, talking about the length argument.

I created a simple expression using -2 as length and was unable to save the expression due to "length cannot accept negative number" (okay, not a direct quote, but teh error was specific and when I changed length to positive number, no issues).
Phil Parkin
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herladygeekedness (8/2/2012)
Not talking about the result, talking about the length argument.

I created a simple expression using -2 as length and was unable to save the expression due to "length cannot accept negative number" (okay, not a direct quote, but teh error was specific and when I changed length to positive number, no issues).




??

The expression I quoted was only the length argument - from the OP's example.


Help us to help you. For better, quicker and more-focused answers to your questions, consider following the advice in this link.

If the answer to your question can be found with a brief Google search, please perform the search yourself, rather than expecting one of the SSC members to do it for you.

Please surround any code or links you post with the appropriate IFCode formatting tags. It helps readability a lot.
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